#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using ll = long long;
using mint = atcoder::modint998244353;

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    auto check = [&](int v){
        int mn = 9, res = 0;
        while(v){
            int r = v % 10;
            res += r;
            if(r > mn) return -1;
            mn = min(mn, r);
            v /= 10;
        }
        return res;
    };
    constexpr int r = 200000;
    vector<bool> tb(r + 1);
    for(int i = 0; i <= 9; i++) tb[i] = true;
    for(int i = 10; i <= r; i++){
        int s = check(i);
        if(s == -1) continue;
        tb[i] = tb[s];
    }
    auto check2 = [&](ll v){
        int mn = 9, res = 0;
        while(v){
            int r = v % 10;
            res += r;
            if(r > mn) return false;
            mn = min(mn, r);
            v /= 10;
        }
        return tb[res] ? true : false;
    };
    array<int, 18> tmp{};
    auto update = [&](ll v){
        int idx = 0;
        while(v){
            int r = v % 10;
            tmp[idx++] = r;
            v /= 10;
        }
        ll res = 0;
        int mx = 0;
        bool flg = false;
        while(idx >= 0){
            if(flg){
                res *= 10;
                res += mx;
            }else{
                if(mx > tmp[idx]){
                    flg = true;
                }else{
                    mx = max(mx, tmp[idx]);
                }
                res *= 10;
                res += mx;
            }
            idx--;
        }
        return res;
    };
    int T;
    cin >> T;
    while(T--){
        ll n;
        cin >> n;
        // 桁和の最低値
        ll mn = n + 1;
        while(!check2(mn)){
            mn = update(mn + 1);
        }
        ll keta = max(n + 1, (mn + 8) / 9);
        mint ans;
        ans += (mint(10).pow(keta) - 1) / 9;
        mn -= keta;
        ll keta2 = mn / 8;
        ans += (mint(10).pow(keta2) - 1) * 8 / 9;
        mn -= keta2 * 8;
        ans += mint(10).pow(keta2) * mn;
        cout << ans.val() << '\n';
    }
}