#pragma GCC optimize("O3") #include "bits/stdc++.h" #include #include "atcoder/all" #include using namespace boost::multiprecision; using namespace std; using namespace atcoder; using ll = long long; using ull = unsigned long long; using mint = modint998244353; using mint2 = modint1000000007; const double eps = 1e-9; #define OVERLOAD3(_1, _2, _3, call,...) call #define REP0(n) for (ll i = 0; i < ll(n); ++i) #define REP1(i, n) for (ll i = 0; i < ll(n); ++i) #define REP2(i, a, b) for (ll i = ll(a); i < ll(b); ++i) #define REP(...) OVERLOAD3(__VA_ARGS__, REP2, REP1, REP0)(__VA_ARGS__) #define RREP0(n) for (ll i = ll(n) - 1; i >= 0; --i) #define RREP1(i, n) for (ll i = ll(n) - 1; i >= 0; --i) #define RREP2(i, a, b) for (ll i = ll(a) - 1; i >= b; --i) #define RREP(...) OVERLOAD3(__VA_ARGS__, RREP2, RREP1, RREP0)(__VA_ARGS__) #define REPE(i, c) for (auto&& i : c) #define TCASE() ll _ttt; cin >> _ttt; while(_ttt--) template void COMMON_IN(T&... a) { (cin >> ... >> a); } #define LI(...) ll __VA_ARGS__; COMMON_IN(__VA_ARGS__); #define SI(...) string __VA_ARGS__; COMMON_IN(__VA_ARGS__); using vl = vector; using vvl = vector; using vvvl = vector; #define VLI(a, n) vector a; a.assign(n, 0); for(auto& x : a) cin >> x; #define DLI(a, n) deque a; a.assign(n, 0); for(auto& x : a) cin >> x; #define VSI(a, n) vector a; a.assign(n, ""); for(auto& x : a) cin >> x; #define VVLI(a, n, m) vector> a(n, vector(m)); for(auto& x : a) for(auto& y : x) cin >> y; using vd = vector; using pl = pair; using vpl = vector; using vvpl = vector; struct uv { ll u; ll v; }; struct uvc { ll u; ll v; ll c = 1; }; #define VUVI(a, n) vector a; a.assign(n, {0, 0}); for(auto& x : a) {cin >> x.u >> x.v; x.u--; x.v--;} #define VUVCI(a, n) vector a; a.assign(n, {0, 0, 0}); for(auto& x : a) {cin >> x.u >> x.v >> x.c; x.u--; x.v--;} vvl to_edge(const ll n, const vector& v) { vvl ret(n); for (auto& x : v) ret[x.u].emplace_back(x.v); return ret; } vvl to_edge_d(const ll n, const vector& v) { vvl ret(n); for (auto& x : v) { ret[x.u].emplace_back(x.v); ret[x.v].emplace_back(x.u); } return ret; } vvpl to_edge_d(const ll n, const vector& v) { vvpl ret(n); for (auto& x : v) { ret[x.u].emplace_back(x.v, x.c); ret[x.v].emplace_back(x.u, x.c); } return ret; } template using pql = priority_queue; template using pqg = priority_queue, greater>; using vm = vector; using vvm = vector; template requires std::is_base_of_v ostream& operator<<(ostream& os, const T& v) { os << v.val(); return os; } void yn(bool f) { std::cout << (f ? "Yes" : "No") << "\n"; }; template void ov(const T& v) { for (auto it = v.begin(); it != v.end(); it++) { if (it != v.begin()) cout << " "; cout << *it; } }; template void ovn(const T& v) { ov(v); cout << "\n"; }; const ll llhuge = 1LL << 61; //十分でかいが多少足しても溢れない数値 auto gmax(const auto& a, const auto& b) { return a > b ? a : b; }; auto gmin(const auto& a, const auto& b) { return a < b ? a : b; }; bool chmin(auto& a, const auto& b) { const auto olda = a; a = gmin(a, b); return olda != a; } bool chmax(auto& a, const auto& b) { const auto olda = a; a = gmax(a, b); return olda != a; } void sort(auto& v) { std::ranges::sort(v); }; void rev(auto& v) { std::ranges::reverse(v); }; template auto p_sum(const T& v) { T ret(v.size()); std::partial_sum(begin(v), end(v), ret.begin()); return ret; }; template [[nodiscard]] V myat(const T& mp, const K& key) { return mp.find(key) == mp.end() ? V() : mp.at(key); } long long ceil(const long long a, const long long b) { return (a + b - 1) / b; } //二分探索でf(t)を満たす整数tを返す //ng < ok ならtは最小値 ng > ok ならtは最大値 template ll bs(ll ok, ll ng, F f) { while (abs(ok - ng) > 1) { ll mid = ok + (ng - ok) / 2; if (f(mid)) ok = mid; else ng = mid; } return ok; } int main() { cin.tie(nullptr); ios::sync_with_stdio(false); LI(n, m); VUVI(e, n - 1); vector dsus(n, dsu(n)); RREP(i, n - 1) { dsus[i] = dsus[i + 1]; dsus[i].merge(e[i].u, e[i].v); } vl imos(n, 0); REP(i, m) { LI(s, t); s--; t--; ll x = bs(0, n-1, [&](ll mid) { return dsus[mid].same(s, t); }); imos[0]++; imos[x + 1]--; } vl ans(n, 0); ans[0] = imos[0]; REP(i, 1, n) { ans[i] = ans[i - 1] + imos[i]; } REP(i, n - 1) { cout << ans[i+1] << "\n"; } }