fn getline() -> String { let mut ret = String::new(); std::io::stdin().read_line(&mut ret).unwrap(); ret } // Segment Tree. This data structure is useful for fast folding on intervals of an array // whose elements are elements of monoid I. Note that constructing this tree requires the identity // element of I and the operation of I. // Verified by: yukicoder No. 2220 (https://yukicoder.me/submissions/841554) struct SegTree { n: usize, orign: usize, dat: Vec, op: BiOp, e: I, } impl SegTree where BiOp: Fn(I, I) -> I, I: Copy { pub fn new(n_: usize, op: BiOp, e: I) -> Self { let mut n = 1; while n < n_ { n *= 2; } // n is a power of 2 SegTree {n: n, orign: n_, dat: vec![e; 2 * n - 1], op: op, e: e} } // ary[k] <- v pub fn update(&mut self, idx: usize, v: I) { debug_assert!(idx < self.orign); let mut k = idx + self.n - 1; self.dat[k] = v; while k > 0 { k = (k - 1) / 2; self.dat[k] = (self.op)(self.dat[2 * k + 1], self.dat[2 * k + 2]); } } // [a, b) (half-inclusive) // http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ #[allow(unused)] pub fn query(&self, rng: std::ops::Range) -> I { let (mut a, mut b) = (rng.start, rng.end); debug_assert!(a <= b); debug_assert!(b <= self.orign); let mut left = self.e; let mut right = self.e; a += self.n - 1; b += self.n - 1; while a < b { if (a & 1) == 0 { left = (self.op)(left, self.dat[a]); } if (b & 1) == 0 { right = (self.op)(self.dat[b - 1], right); } a = a / 2; b = (b - 1) / 2; } (self.op)(left, right) } } // https://yukicoder.me/problems/no/3313 (3) // 区間の交差 + クエリー問題 fn main() { let n = getline().trim().parse::().unwrap(); let mut rl = vec![]; for _ in 0..n { let ints = getline().trim().split_whitespace() .map(|x| x.parse::().unwrap()) .collect::>(); rl.push((ints[1], ints[0])); } rl.sort(); const W: usize = 1_000_001; let mut st = SegTree::new(W, |x, y| x + y, 0); let mut ans = 0i64; for (_, l) in rl { ans += st.query(l..W); let old = st.query(l..l + 1); st.update(l, old + 1); } println!("{ans}"); }