#include #include #include #include #include #include #include using namespace std; using namespace atcoder; using ll = long long; using mint = modint998244353; using vi = vector; using vvi = vector; using vvvi = vector; using vll = vector; using vvll = vector; using vvvll = vector; using vmi = vector; using vvmi = vector; using vvvmi = vector; #define all(a) (a).begin(), (a).end() #define rep2(i, m, n) for (int i = (m); i < (n); ++i) #define rep(i, n) rep2(i, 0, n) #define drep2(i, m, n) for (int i = (m)-1; i >= (n); --i) #define drep(i, n) drep2(i, n, 0) void solve(){ } int main(){ int n; cin >> n; map mp; vi x(n), a(n); rep(i, n){ cin >> x[i]; mp[x[i]] = i; } vvi adj(n); scc_graph scc(n); rep(i, n){ cin >> a[i]; if(mp.count((x[i] + a[i]))){ adj[i].push_back(mp[x[i] + a[i]]); scc.add_edge(i, mp[x[i] + a[i]]); }if(mp.count((x[i] - a[i]))){ adj[i].push_back(mp[x[i] - a[i]]); scc.add_edge(i, mp[x[i] - a[i]]); } } vvi g = scc.scc(); reverse(all(g)); vi ans(n, -1); for(auto v : g){ int b = 0; for(auto i : v){ b = max(b, x[i] + a[i]); for(auto j : adj[i])b = max(b, ans[j]); } for(auto i : v)ans[i] = b; }rep(i, n)cout << ans[i] - x[i]<< endl; return 0; }