#include <iostream>

using namespace std;

typedef long long LL;

const int N = 4480;

int n;
LL ans;

void Solve() {
    for (int i = N - 1; i >= 1; --i) {
        ans += n / (i * (i + 1) / 2);
        n %= i * (i + 1) / 2;
    }
    printf("%lld\n", ans);
}

int main() {
    // freopen("coin.in", "r", stdin);
    // freopen("coin.out", "w", stdout);

    scanf("%d", &n);

    Solve();

    return 0;
}