#include #include using namespace std; using namespace atcoder; #define rep(i, a, n) for(int i = a; i < n; i++) #define rrep(i, a, n) for(int i = a; i >= n; i--) #define inr(l, x, r) (l <= x && x < r) #define ll long long #define ld long double // using mint = modint1000000007; using mint = modint998244353; constexpr int IINF = 1001001001; constexpr ll INF = 1e18; template void chmax(t&a,u b){if(a void chmin(t&a,u b){if(b> n; vector c(n); rep(i, 0, n){ cin >> c[i]; } if(n%2 == 1){ sort(c.begin(), c.end()); mint ans = mint(c[0])*mint(10).pow(n/2); mint ten = 1; rrep(i, n/2, 1){ ans += ten*c[i]; ten *= 10; } ten /= 10; rrep(i, n-1, n/2+1){ ans -= ten*c[i]; ten /= 10; } cout << ans.val() << endl; }else{ vector cnt(10); rep(i, 0, n) cnt[c[i]]++; vector p; rep(i, 1, 10){ if(cnt[i]%2 == 1) p.emplace_back(i); } int m = (int)p.size(); int ans = IINF; do{ int x = 0, y = 0; int ten = 1; rep(i, 0, m/2){ x += ten*p[i]; ten *= 10; } ten /= 10; rep(i, m/2, m){ y += ten*p[i]; ten /= 10; } chmin(ans, abs(x-y)); }while(next_permutation(p.begin(), p.end())); if(m == 0) ans = 0; cout << ans << endl; } return 0; }