#include using namespace std; typedef signed long long ll; #define _P(...) (void)printf(__VA_ARGS__) #define FOR(x,to) for(x=0;x<(to);x++) #define FORR(x,arr) for(auto& x:arr) #define FORR2(x,y,arr) for(auto& [x,y]:arr) #define ALL(a) (a.begin()),(a.end()) #define ZERO(a) memset(a,0,sizeof(a)) #define MINUS(a) memset(a,0xff,sizeof(a)) template bool chmax(T &a, const T &b) { if(a bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;} //------------------------------------------------------- int N,M,C; vector> E[202020]; ll dp[3][202020]; void solve() { int i,j,k,l,r,x,y; string s; cin>>N>>M>>C; FOR(i,M) { cin>>x>>y>>k; E[x-1].push_back({y-1,k+C}); E[y-1].push_back({x-1,k+C}); } FOR(i,N) dp[0][i]=dp[1][i]=dp[2][i]=1LL<<60; priority_queue> Q; dp[0][0]=dp[1][N-1]=dp[2][N-1]=0; Q.push({0,0}); Q.push({0,N+N-1}); Q.push({0,2*N+N-1}); while(Q.size()) { ll co=-Q.top().first; int cur=Q.top().second%N; int id=Q.top().second/N; Q.pop(); if(dp[id][cur]!=co) continue; FORR2(e,c,E[cur]) if(chmin(dp[id][e],co+c)) Q.push({-dp[id][e],id*N+e}); if(id==1) { FORR2(e,c,E[cur]) if(chmin(dp[2][e],co+C)) Q.push({-dp[2][e],2*N+e}); } } ll ret=dp[0][N-1]; for(i=1;i