#include #include using namespace std; using namespace atcoder; typedef long long ll; #define rep(i, n) for (ll i = 0; i < (ll)(n); i++) static const double pi = 3.141592653589793; const ll INF = 1LL << 60; const ll mod = 1000000007; const ll imod = 998244353; using mint = modint998244353; vector dx = {1, 0, -1, 0}, dy = {0, 1, 0, -1}; ll P(ll x, ll n) { ll ret = 1; while (n > 0) { if (n & 1) ret *= x; x *= x; n >>= 1; } return ret; } void seek(bool f){ cout << (f ? "Yes" : "No") << endl; } int main(){ int N; cin >> N; string s; cin >> s; int dp[N + 1][3]; rep(i, N + 1){ rep(j, 3){ dp[i][j] = -1e9; } } dp[0][0] = 0; for(int i = 0; i < N; i++){ for(int j = 0; j < 3; j++){ dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]); } if(s[i] == '+'){ dp[i + 1][2] = max({dp[i + 1][2], max({dp[i][0], dp[i][1], dp[i][2]}) + 1}); } if(s[i] == '0'){ dp[i + 1][1] = max(dp[i + 1][1], dp[i][0] + 1); } if(s[i] == '-'){ dp[i + 1][0] = max(dp[i + 1][0], dp[i][0] + 1); } } cout << max({dp[N][0], dp[N][1], dp[N][2]}) << endl; }