#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------

int T,N,A;
ll dp[2525][2525];
const ll mo=998244353;
vector<int> D[252525];

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	for(i=1;i<=250000;i++) {
		for(j=i;j<=250000;j+=i) D[j].push_back(i);
	}
	
	
	dp[0][0]=1;
	FOR(i,2125) FOR(j,2125) {
		if(j) (dp[i+1][j-1]+=dp[i][j])%=mo;
		(dp[i+1][j+1]+=dp[i][j])%=mo;
	}
	
	cin>>T;
	while(T--) {
		cin>>N>>A;
		ll ret=0;
		
		FORR(d,D[A]) {
			if(A/d<=N-1) ret+=dp[N-1][A/d];
		}
		cout<<ret%mo<<endl;
		
	}
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}