#include <algorithm>
#include <atcoder/all>
#include <bitset>
#include <cassert>
#include <cmath>
#include <ctime>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using namespace atcoder;
typedef long long ll;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--)
#define repk(i, k, n) for (int i = k; i < (int)(n); i++)
#define all(v) v.begin(), v.end()
#define mod1 1000000007
#define mod2 998244353
#define mod3 100000007
#define vi vector<int>
#define vs vector<string>
#define vc vector<char>
#define vl vector<ll>
#define vb vector<bool>
#define vvi vector<vector<int>>
#define vvc vector<vector<char>>
#define vvl vector<vector<ll>>
#define vvb vector<vector<bool>>
#define vvvi vector<vector<vector<int>>>
#define vvvl vector<vector<vector<ll>>>
#define pii pair<int, int>
#define pil pair<int, ll>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define vpii vector<pair<int, int>>
#define vpll vector<pair<ll, ll>>
#define vvpii vector<vector<pair<int, int>>>
#define vvpll vector<vector<pair<ll, ll>>>

template <typename T>
void debug(T e) {
    cerr << e << endl;
}

template <typename T>
void debug(vector<T> &v) {
    rep(i, v.size()) { cerr << v[i] << " "; }
    cerr << endl;
}

template <typename T>
void debug(vector<vector<T>> &v) {
    rep(i, v.size()) {
        rep(j, v[i].size()) { cerr << v[i][j] << " "; }
        cerr << endl;
    }
}

template <typename T>
void debug(vector<pair<T, T>> &v) {
    rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; }
}

template <typename T>
void debug(set<T> &st) {
    for (auto itr = st.begin(); itr != st.end(); itr++) {
        cerr << *itr << " ";
    }
    cerr << endl;
}

template <typename T>
void debug(multiset<T> &ms) {
    for (auto itr = ms.begin(); itr != ms.end(); itr++) {
        cerr << *itr << " ";
    }
    cerr << endl;
}

template <typename T>
void debug(map<T, T> &mp) {
    for (auto itr = mp.begin(); itr != mp.end(); itr++) {
        cerr << itr->first << " " << itr->second << endl;
    }
}

void debug_out() { cerr << endl; }

template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
    cerr << H << " ";
    debug_out(T...);
}

using mint = modint1000000007;

void debug_mint1(vector<mint> &vec) {
    for (int i = 0; i < vec.size(); i++) {
        cerr << vec[i].val() << " ";
    }
    cerr << endl;
}

void debug_mint2(vector<vector<mint>> &vec) {
    for (int i = 0; i < vec.size(); i++) {
        for (int j = 0; j < vec[i].size(); j++) {
            cerr << vec[i][j].val() << " ";
        }
        cerr << endl;
    }
}

void dijkstra(vvpll &graph, ll v, vl &dist) {
    priority_queue<pll, vpll, greater<pll>> pque;
    pque.push(pll(0, v));
    dist[v] = 0;
    while (pque.size()) {
        pll p = pque.top();
        pque.pop();
        if (dist[p.second] != p.first) {
            continue;
        }
        for (auto x : graph[p.second]) {
            if (dist[x.first] > dist[p.second] + x.second) {
                dist[x.first] = dist[p.second] + x.second;
                pque.push(pll(dist[x.first], x.first));
            }
        }
    }
}

int main() {
    ll N, M, P, Q, T;
    cin >> N >> M >> P >> Q >> T;
    P--;
    Q--;
    vector<ll> a(M);
    vector<ll> b(M);
    vector<ll> c(M);
    for (ll i = 0; i < M; i++){
        cin >> a[i] >> b[i] >> c[i];
        a[i]--;
        b[i]--;
    }
    vector<vector<pll>> graph(N, vector<pll>(0));
    for (ll i = 0; i < M; i++){
        graph[a[i]].push_back(make_pair(b[i], c[i]));
        graph[b[i]].push_back(make_pair(a[i], c[i]));
    }
    ll INF = 100000000000000023;
    vector<ll> d1(N, INF);
    vector<ll> dp(N, INF);
    vector<ll> dq(N, INF);

    dijkstra(graph, 0, d1);
    dijkstra(graph, P, dp);
    dijkstra(graph, Q, dq);

    ll ans = -1;
    // 行き帰りの合流地点を全探索したい
    for (ll i = 0; i < N; i++){
        for (ll j = 0; j < N; j++){
            if (d1[i] + dp[i] + dp[j] + d1[j] <= T && d1[i] + dq[i] + dq[j] + d1[j] <= T){
                ans = max(ans, min(T - dp[i] - dp[j], T - dq[i] - dq[j]));
            }
        }
    }
    // 全部居られるならそうする
    if (d1[P] + dp[Q] + dq[0] <= T){
        ans = T;
    }
    cout << ans << endl;
}