#include using namespace std; using ll=long long; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using _pq = priority_queue, greater>; template int LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template int UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(b bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=false){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} template T square(T a){return a * a;} #include using mint = atcoder::modint998244353; struct F{ mint c = 0; mint v = 0; }; F operator*(F a, F b){ return {a.c * b.c, a.c * b.v + a.v * b.c}; } F operator+(F a, F b){ return {a.c + b.c, b.v + a.v}; } void solve(); // DEAR MYSTERIES / TOMOO int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; // cin >> t; rep(i, 0, t) solve(); } void solve(){ int N, K; cin >> N >> K; vector A(N); rep(i, 0, N) cin >> A[i]; vector dp1(K + 1), dp2(K + 1); dp1[0] = {1, 0}; rep(rp, 0, N){ for (int i = K; i > 0; i--){ dp2[i - 1] = dp2[i - 1] + dp2[i]; } dp2[K] = dp2[K] + dp1[K]; dp1[K] = {0, 0}; rep(i, 0, K){ dp1[i + 1] = dp1[i + 1] + dp1[i]; } mint p2 = 1, pa = 1; rep(i, 0, K + 1){ F tmp = {p2, pa * p2}; dp1[i] = dp1[i] * tmp; dp2[i] = dp2[i] * tmp; p2 *= 2, pa *= A[rp]; } } mint ans = 0; rep(i, 0, K + 1) ans += dp2[i].v; ans /= (mint(4)).pow(K); cout << ans.val() << "\n"; }