#include using namespace std; using ll=long long; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using pq_ = priority_queue, greater>; template int LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template int UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(b bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=false){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(int)(a&1),a>>=1;}return res;} template T square(T a){return a * a;} #include using mint = atcoder::modint998244353; using F = array, 4>; F e(){ F tmp; rep(i, 0, 4) rep(j, 0, 4) tmp[i][j] = 0; return tmp; } F mul(F l, F r){ F res = e(); rep(i, 0, 4) rep(j, 0, 4) rep(k, 0, 4){ res[i][k] += l[i][j] * r[j][k]; } return res; } F my_pow(F l, int t){ F res = e(); rep(i, 0, 4) res[i][i] = 1; while (t){ if (t & 1) res = mul(res, l); l = mul(l, l); t /= 2; } return res; } void solve(); // DEAR MYSTERIES / TOMOO int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; // cin >> t; rep(i, 0, t) solve(); } void solve(){ const int L = 10'000'100; vector E(L, 1), X(L); E[0] = 0, E[1] = 0; rep(i, 2, L) if (E[i] == 1){ for (int j = i * 2; j < L; j += i) E[j] = 0; } rep(i, 0, L - 10) if (E[i] == 1){ if (E[i ^ 2] == 1 && (i & 2) == 2){ X[i] = 1; } } auto Es = E; rep(i, 0, L - 1) X[i + 1] += X[i], Es[i + 1] += Es[i]; int T; cin >> T; while (T--){ int N, M; cin >> N >> M; if (N == 1){ cout << Es[M] << "\n"; } else{ F dp = e(); rep(i, 1, 4) rep(j, 1, 4) if (i != j){ dp[i][j ^ i] = 1; if (i == 1) dp[i][j ^ i] = X[M]; } dp = my_pow(dp, N - 1); mint ans = 0; rep(i, 1, 4) rep(j, 1, 4){ if (i == 1) ans += dp[i][j]; else ans += dp[i][j] * X[M]; } cout << ans.val() << "\n"; } } } /* * P[i] != 2 であるものは高々 1 つしか存在しない * P[0] , P[1] のいずれかは 2 以下である */