// g++ -Wall -std=gnu++20 -march=native -O2 -static -DAWASHAMITYOAK #ifdef AWASHAMITYOAK #include #else #include #include #endif using namespace std; using namespace atcoder; using ll = long long; using ld = long double; using mint = modint998244353; istream& operator>> (istream& is, mint& x) { long long _x; is >> _x; x = _x; return is; } ostream& operator<< (ostream& os, const mint& x) { return os << x.val(); } template ostream& operator<< (ostream& os, const pair& x) { return os << "{" << x.first << ", " << x.second << "}"; } #define OVERLOAD_REP(_1, _2, _3, name, ...) name #define REP2(i, l, r) for (int i = (int)(l); i < (int)(r); ++i) #define REP1(i, n) REP2(i, 0, n) #define rep(...) OVERLOAD_REP(__VA_ARGS__, REP2, REP1)(__VA_ARGS__) #define RREP2(i, r, l) for (int i = (int)(r)-1; i >= (int)(l); --i) #define RREP1(i, n) RREP2(i, n, 0) #define rrep(...) OVERLOAD_REP(__VA_ARGS__, RREP2, RREP1)(__VA_ARGS__) #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define pb push_back #define mp make_pair #define mt make_tuple const ll INF = 4e18; const ll MOD = 998244353; const ll MOD1 = 1e9 + 7; template inline bool chmax(T &a, T b) { return a < b ? a = b, 1 : 0; } template inline bool chmin(T &a, T b) { return a > b ? a = b, 1 : 0; } template T pow(T a, T b, T m) { return b ? b&1 ? a*pow(a, b^1, m)%m : pow(a*a%m, b>>1, m)%m : 1; } template T pow(T a, T b) { return b ? b&1 ? pow(a, b^1)*a : pow(a*a, b>>1) : 1; } template inline void input(T&... a) { ((cin >> a), ...); } template inline void print(const T& a, const U&... b) { cout << a; ((cout << " " << b), ...); } template inline void println(const T& a, const U&... b) { print(a, b...); cout << endl; } inline void println() { cout << endl; } template inline void print(vector& A) { rep(i, A.size()) if (i) print("", A[i]); else print(A[i]); } template inline void println(vector& A) { print(A); cout << endl; } const int di[8] = {-1, 0, 1, 0, -1, -1, 1, 1}; const int dj[8] = {0, -1, 0, 1, -1, 1, -1, 1}; #define int ll void solve() { int N; input(N); vector A(N); rep(i, N) input(A[i]); auto fn = [](int A) -> pair { int t = 0, f = 0; string S = to_string(A); while (A != 0) { while (S.back() == '0') S.pop_back(); int k = 1; rep(i, S.size()) k *= 10; A = stoll(S); if (A % 2 == 0) { f++; A *= 5; A %= k; } else { t++; A *= 2; A %= k; } int p = S.size(); S = to_string(A); S = string(p - S.size(), '0') + S; } return {t, f}; }; int two = 0; int five = 0; rep(i, 1, N) { auto [t, f] = fn(A[i]); chmax(two, t); chmax(five, f); } int ans = 1; rep(i, two) ans *= 2; rep(i, five) ans *= 5; println(ans); } signed main() { ios::sync_with_stdio(false); cin.tie(nullptr); int T; input(T); rep(t, T) solve(); }