#include using namespace std; using ll=long long; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using pq_ = priority_queue, greater>; template int LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template int UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(b bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=false){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(int)(a&1),a>>=1;}return res;} template T square(T a){return a * a;} #include int op(int a, int b){ return a + b; } int e(){ return 0; } int target; bool f(int x){ return x <= target; } void solve(); // DEAR MYSTERIES / TOMOO int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; // cin >> t; rep(i, 0, t) solve(); } void solve(){ int N, Q; cin >> N >> Q; vector A(N + Q), ind(N + Q), L(N + Q), R(N + Q); rep(i, 0, N){ cin >> A[i]; ind[i] = i; } rep(i, N, N + Q){ cin >> ind[i] >> A[i] >> L[i] >> R[i]; L[i]--; } atcoder::segtree seg(vector(N + Q, 1)); for (int i = N + Q - 1; i >= 0; i--){ target = ind[i]; ind[i] = seg.max_right(0); seg.set(ind[i], 0); // cout << "# " << ind[i] << "\n"; } atcoder::segtree seg_val(N + Q); auto g = [&](int ind) -> int { target = ind; return seg_val.prod(0, seg.max_right(0)); }; rep(i, 0, N + Q){ seg.set(ind[i], 1); seg_val.set(ind[i], A[i]); if (i >= N) cout << g(R[i]) - g(L[i]) << "\n"; } }