#include <bits/stdc++.h>
using namespace std;

//入力が必ず-mod<a<modの時.
template<int idx> //modが入力で与えられる場合.
struct dynamic_modint{ //mod変更が可能 最初にsetmod必須 idxで複数個所持が可能.
    private:
    static int mod;
    public:
    long long v;
    static constexpr long long getmod(){return mod;}
    static void setmod(int m){
        assert(m > 0);
        mod = m;
    }
    dynamic_modint():v(0){}
    template<typename T>
    dynamic_modint(T a):v(a){if(v < 0) v += mod;}
    long long val()const{return v;}
 
    dynamic_modint &operator=(const dynamic_modint &b) = default;
    dynamic_modint &operator+()const{return (*this);}
    dynamic_modint operator-()const{return dynamic_modint(0)-(*this);}
    dynamic_modint operator+(const dynamic_modint b)const{return dynamic_modint(v)+=b;}
    dynamic_modint operator-(const dynamic_modint b)const{return dynamic_modint(v)-=b;}
    dynamic_modint operator*(const dynamic_modint b)const{return dynamic_modint(v)*=b;}
    dynamic_modint operator/(const dynamic_modint b)const{return dynamic_modint(v)/=b;}
    dynamic_modint &operator+=(const dynamic_modint b){
        v += b.v; if(v >= mod) v -= mod;
        return *this;
    }
    dynamic_modint &operator-=(const dynamic_modint b){
        v -= b.v; if(v < 0) v += mod;
        return *this;
    }   
    dynamic_modint &operator*=(const dynamic_modint b){v = v*b.v%mod; return *this;}
    dynamic_modint &operator/=(dynamic_modint b){ //b!=0 mod素数が必須.
        assert(b.v != 0);
        (*this) *= b.pow(mod-2);
        return *this;
    }
    dynamic_modint pow(long long n)const{
        dynamic_modint ret = 1,p = v;
        if(n < 0) p = p.inv(),n = -n;
        while(n){if(n&1) ret *= p; p *= p,n >>= 1;}
        return ret;
    }
    dynamic_modint inv()const{return pow(mod-2);} //素数mod必須.
 
    dynamic_modint &operator++(){*this += 1; return *this;}
    dynamic_modint &operator--(){*this -= 1; return *this;}
    dynamic_modint operator++(int){dynamic_modint ret = *this; *this += 1; return ret;}
    dynamic_modint operator--(int){dynamic_modint ret = *this; *this -= 1; return ret;}
    friend bool operator==(const dynamic_modint a,const dynamic_modint b){return a.v==b.v;}
    friend bool operator!=(const dynamic_modint a,const dynamic_modint b){return a.v!=b.v;}
    friend bool operator<(const dynamic_modint a,const dynamic_modint b){return a.v<b.v;}
    friend bool operator<=(const dynamic_modint a,const dynamic_modint b){return a.v<=b.v;}
    friend bool operator>=(const dynamic_modint a,const dynamic_modint b){return a.v>=b.v;}
    friend bool operator>(const dynamic_modint a,const dynamic_modint b){return a.v>b.v;}
    friend ostream &operator<<(ostream &os,const dynamic_modint a){return os<<a.v;}
    friend istream &operator>>(istream &is,dynamic_modint &a){ //入力はmodをとってくれる.
        long long x; is >> x; x %= mod;
        a = dynamic_modint(x); return is;
    }
    
};
template<int idx> int dynamic_modint<idx>::mod=998244353;
using mint = dynamic_modint<0>;

template<typename T>
vector<vector<T>> multima(vector<vector<T>> &A,vector<vector<T>> &B){
    assert(A.at(0).size() == B.size() && B.size());
    int H = A.size(),W = B.at(0).size();
    vector<vector<T>> ret(H,vector<T>(W));
    for(int i=0; i<H; i++) for(int k=0; k<W; k++){
        for(int l=0; l<A.at(i).size(); l++){
            ret.at(i).at(k) += A.at(i).at(l)*B.at(l).at(k);
        }
    }
    return ret; //計算できる行列のみ.
}
template<typename T>
vector<vector<T>> Powmat(vector<vector<T>> A,vector<vector<T>> B,long long N){ //return A^N*B ABは行列;
    //n*n行列A n*1行列Bと想定 O(n^3*logN).
    assert(A.size() && A.size() == A.at(0).size() && N >= 0);
    while(N){
        if(N&1) B = multima(A,B);
        A = multima(A,A); N >>= 1;
    }
    return B;
}

int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);

    int T; cin >> T;
    while(T--){
        long long N,M,L,mod; cin >> N >> M >> L >> mod;
        mint::setmod(mod);
        M %= mod,L %= mod;
        vector<vector<mint>> A = {
            {0,M,L,0},
            {1,0,0,L},
            {1,0,0,M},
            {0,1,1,0}
        },B = {{1},{0},{0},{0}};
        B = Powmat(A,B,N);
        if(N%2) cout << B.at(2).at(0) << "\n";
        else cout << B.at(0).at(0) << "\n";
    }
}