#include using namespace std; using ll = long long; void answer() { int n, m; cin >> n >> m; int z; z = (n - (2 * m)) / 10; if (z < 0) { z = 0; } n -= 2 * z; m += 4 * z; int a = min((m / 2),(n / 4)); a = max (a, min(((n - 2) / 4), (m + 4) / 2)); cout << 3 * a << endl; return; } int main() { int t; cin >> t; for (int i = 0; i < t; i++) { answer(); } return 0; }