import sys import math class UnionFind: def __init__(self, n): self.par = list(range(n)) self.rank = [0] * n def find(self, x): if self.par[x] != x: self.par[x] = self.find(self.par[x]) return self.par[x] def unite(self, x, y): x = self.find(x) y = self.find(y) if x == y: return if self.rank[x] < self.rank[y]: self.par[x] = y else: self.par[y] = x if self.rank[x] == self.rank[y]: self.rank[x] += 1 def same(self, x, y): return self.find(x) == self.find(y) def main(): input = sys.stdin.readline N = int(input()) if N == 0: # 中継局なし → 直接通信のみ print(1) return points = [] for _ in range(N): x, y = map(int, input().split()) points.append((x, y)) uf = UnionFind(N) # 中継局間の距離が 10km 以下なら同じ連結成分にする for i in range(N): x1, y1 = points[i] for j in range(i + 1, N): x2, y2 = points[j] dx = x1 - x2 dy = y1 - y2 dist2 = dx * dx + dy * dy if dist2 <= 100: # 10^2 uf.unite(i, j) # 連結成分ごとに頂点を集める comp = {} for i in range(N): r = uf.find(i) if r not in comp: comp[r] = [] comp[r].append(i) ans = 2.0 # 中継局が1本以上あれば、最低でも 2km は可能 # 各成分内で最大距離を調べる for root, nodes in comp.items(): m = len(nodes) if m == 1: # 1本だけの成分では d = 0 → d + 2 = 2 なので、既に ans に反映済み continue max_d2 = 0 for i in range(m): x1, y1 = points[nodes[i]] for j in range(i + 1, m): x2, y2 = points[nodes[j]] dx = x1 - x2 dy = y1 - y2 d2 = dx * dx + dy * dy if d2 > max_d2: max_d2 = d2 d = math.sqrt(max_d2) ans = max(ans, d + 2.0) print("{:.10f}".format(ans)) if __name__ == "__main__": main()