#include #define rep(i, p, n) for (ll i = p; i < (ll)(n); i++) #define rep2(i, p, n) for (ll i = p; i >= (ll)(n); i--) using namespace std; using ll = long long; using ld = long double; const double pi = 3.141592653589793; const long long inf = 2 * 1e9; const long long linf = 4 * 1e18; const ll mod1 = 1000000007; const ll mod2 = 998244353; template inline bool chmax(T &a, T b) { if (a < b) { a = b; return 1; } return 0; } template inline bool chmin(T &a, T b) { if (a > b) { a = b; return 1; } return 0; } template using priority_queue_rev = priority_queue, greater>; // atcoder #include using namespace atcoder; using mint1 = modint1000000007; using mint2 = modint998244353; vector> base = {{0, 1}, {-1, 0}, {0, -1}, {1, 0}}; void solve() { ll N, L, H; cin >> N >> L >> H; vector C(N); rep(i, 0, N) { cin >> C.at(i); } ll ans = 0; rep(i, 1, (1 << N)) { ll G = 1, co = 0; bool ch = true; rep(j, 0, N) { if (i & (1 << j) && G <= 1e9) { G = lcm(G, C.at(j)); co++; } if (G > 1e9) { ch = false; } } if (ch) { if (co%2==1) { ans += co * (H / G - (L - 1) / G); } else { ans -= co * (H / G - (L - 1) / G); } } } cout << ans << endl; } int main() { ////////////////// ios::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); ////////////////// solve(); }