#include using namespace std; using ll=long long; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using pq_ = priority_queue, greater>; template int LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template int UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(b bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=false){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(int)(a&1),a>>=1;}return res;} template T square(T a){return a * a;} #include using mint = atcoder::modint998244353; void solve(); // DEAR MYSTERIES / TOMOO int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; // cin >> t; rep(i, 0, t) solve(); } void solve(){ int N, Q; cin >> N >> Q; vector A(N); rep(i, 0 ,N) cin >> A[i]; So(A); A.erase(unique(all(A)), A.end()); vector> p; N = A.size(); for (int l = 0, r = 0; l < N; l = r) { while (r != N && A[l] - l == A[r] - r) { r++; } p.push_back({A[l], A[r - 1] + 1}); } auto f = [&](vector> v, ll m) -> vector> { ll sum = 0; vector> res; rep(i, 1, v.size()) { if (sum == m) break; ll l = v[i - 1].second; ll r = v[i].first; chmin(r, l + m - sum); sum += r - l; res.push_back({l, r}); } if (sum != m) res.push_back({v.back().second, v.back().second + m - sum}); return res; }; mint base = 0; while (Q--) { ll K, X, M; cin >> K >> X >> M; auto ans = p; if (K < 3) { while (K) { K--; ans = f(ans, M); } } else { ans = f(ans, M); ans = f(ans, M); K -= 2; auto ans2 = f(ans, M); assert(ans.size() == ans2.size()); int sz = ans2.size(); base += (K / (sz * 2)) * M * 2; K %= (sz * 2); if (K % 2 == 1) { swap(ans, ans2); } rep(rp, 0, K / 2) { ans.push_back({ans[rp].first + M * 2, ans[rp].second + M * 2}); } ans.erase(ans.begin(), ans.begin() + (K / 2)); } X--; for (auto [l, r] : ans) { if (X >= r - l) { X -= r - l; } else { cout << (base + X + l).val() << "\n"; break; } } p = ans; } } /* * 今ある数字の小さい方から N 個 * 今ない数字の小さい方から N 個を管理するとか? * Mi が固定なのがポイントか * */