#include #include using namespace atcoder; using namespace std; using ll = long long; using mint = modint998244353; int main() { ll n; cin >> n; mint ans; if (n%2 == 0) ans = 7*mint(2).pow(n/2); else ans = 5*mint(2).pow((n+1)/2); ans -= 2*n+6; cout << ans.val() << '\n'; return 0; }