#include #include using namespace std; using namespace atcoder; #define rep(i, n) REP(i, 0, n) #define REP(i, s, e) for (ll i = (s); i < (ll)(e); i++) #define repr(i, n) REPR(i, n, 0) #define REPR(i, s, e) for (ll i = (ll)(s - 1); i >= (ll)(e); i--) #define all(r) r.begin(), r.end() #define rall(r) r.rbegin(), r.rend() typedef long long ll; typedef vector vi; typedef vector vl; template bool chmax(T& a, const U& b) { if (a >= b) return false; a = b; return true; } template bool chmin(T& a, const U& b) { if (a <= b) return false; a = b; return true; } void yes_no(bool f, string yes = "Yes", string no = "No") { cout << (f ? yes : no) << "\n"; } struct Sieve { vector primes; vector _isPrime; vector prime_factor_num; // soinsuu no kosuu Sieve(int n) : _isPrime(n + 1, 1), prime_factor_num(n + 1, 0) { buildPrimes(); } void buildPrimes() { _isPrime[0] = _isPrime[1] = 0; int n = _isPrime.size(); REP(i, 2, n) { if (_isPrime[i]) { primes.push_back(i); prime_factor_num[i] = 1; for (int j = i + i; j < n; j += i) _isPrime[j] = 0, prime_factor_num[j]++; } } } bool isPrime(int i) { return _isPrime[i]; } }; void solve() { int n; cin >> n; vl a(n); rep(i, n) cin >> a[i]; const int ma = (int)1e4 + 10; map cnt; using P = pair; vector, greater

>> v(ma); rep(i, n) { cnt[a[i]]++; for (ll j = 1; j * j <= a[i]; ++j) if (a[i] % j == 0) { v[j].emplace(a[i], i); v[a[i] / j].emplace(a[i], i); } } vl ans; rep(i, n) { ans.emplace_back(a[i]); cnt[a[i]]--; ll mi = 1e9, val; for (ll j = 1; j * j <= a[i]; ++j) if (a[i] % j == 0) { while (v[j].size()) { auto [x, k] = v[j].top(); if (cnt[x] == 0) { v[j].pop(); continue; } auto y = a[i] * x / __gcd(a[i], x); if (chmin(mi, y)) { val = x; } break; } while (v[a[i] / j].size()) { auto [x, k] = v[a[i] / j].top(); if (cnt[x] == 0) { v[a[i] / j].pop(); continue; } auto y = a[i] * x / __gcd(a[i], x); if (chmin(mi, y)) { val = x; } break; } } if (i + 1 < n) a[i + 1] = val; } rep(i, ans.size()) cout << ans[i] << (i + 1 == (int)ans.size() ? '\n' : ' '); } int main() { cin.tie(0); ios::sync_with_stdio(false); int t = 1; // cin >> t; rep(ti, t) solve(); return 0; }