#include #include #include using namespace std; using ll = long long; int used[10]={7,2,6,6,5,6,7,3,6,5}; int main(void){ int n; cin >> n; int d=n/2; for(int i=0; i=0; j--){ int nxt=n-used[j]; int must=2*(d-1-i); if(nxt>=must){ n-=used[j]; cout << j; break; } } if(i==d-1) cout << endl; } return 0; }