#include #include using namespace std; using namespace atcoder; #define rep(i, n) REP(i, 0, n) #define REP(i, s, e) for (ll i = (s); i < (ll)(e); i++) #define repr(i, n) REPR(i, n, 0) #define REPR(i, s, e) for (ll i = (ll)(s - 1); i >= (ll)(e); i--) #define all(r) r.begin(), r.end() #define rall(r) r.rbegin(), r.rend() typedef long long ll; typedef vector vi; typedef vector vl; template bool chmax(T& a, const U& b) { if (a >= b) return false; a = b; return true; } template bool chmin(T& a, const U& b) { if (a <= b) return false; a = b; return true; } void yes_no(bool f, string yes = "Yes", string no = "No") { cout << (f ? yes : no) << "\n"; } const ll mod = (ll)1e9 + 9; const int ma = (int)2e5 + 10; vector dp(ma); vector ep(ma); void precalc() { dp[0] = 1; for (int j = 1; j < 10; ++j) { rep(i, ma) if (i + j < ma) { (dp[j + i] += dp[i]) %= mod; } } ep[0] = dp[0]; REP(i, 1, ma) { ep[i] = (ep[i - 1] + dp[i]) % mod; } } void solve() { ll m; cin >> m; ll x = m / 111111; ll ans = ep[x]; cout << ans << "\n"; } int main() { cin.tie(0); ios::sync_with_stdio(false); int t = 1; precalc(); cin >> t; rep(ti, t) solve(); return 0; }