fn getline() -> String { let mut ret = String::new(); std::io::stdin().read_line(&mut ret).unwrap(); ret } // Minimum cost flow. // Verified by: yukicoder No.1301 Strange Graph Shortest Path // (https://yukicoder.me/submissions/590401) // AtCoder Library Practice Contest - E // (https://atcoder.jp/contests/practice2/submissions/22478556) // ACL Contest 1 - C // (https://atcoder.jp/contests/acl1/submissions/23898415) type Cap = isize; type Cost = i64; #[derive(Debug, Clone, Copy)] struct Edge { to: usize, cap: Cap, cost: Cost, rev: usize, // rev is the position of reverse edge in graph[to] } #[derive(Debug, Clone)] struct MinCostFlow { n: usize, graph: Vec>, h: Vec, // potential, dist: Vec, // minimum distance prev: Vec<(usize, usize)>, // previous vertex and edge } impl MinCostFlow { // Initializes this solver. n is the number of vertices. fn new(n: usize) -> Self { MinCostFlow { n: n, graph: vec![vec![]; n], h: vec![0; n], dist: vec![0; n], prev: vec![(0, 0); n], } } fn add_edge(&mut self, from: usize, to: usize, cap: Cap, cost: Cost) { let fst = Edge { to: to, cap: cap, cost: cost, rev: self.graph[to].len(), }; self.graph[from].push(fst); let snd = Edge { to: from, cap: 0, cost: -cost, rev: self.graph[from].len() - 1, }; self.graph[to].push(snd); } // Calcucates the minimum cost flow // whose source is s, sink is t, and flow is f. fn min_cost_flow(&mut self, s: usize, t: usize, mut f: Cap) -> Cost { let n = self.n; let inf: Cost = std::i64::MAX / 10; // ????? let mut res = 0; let h = &mut self.h; let dist = &mut self.dist; while f > 0 { let mut que = std::collections::BinaryHeap::<(Cost, usize)>::new(); for i in 0..n { dist[i] = inf; } dist[s] = 0; que.push((0, s)); while let Some((d, v)) = que.pop() { let d = -d; if dist[v] < d { continue; } for (i, &e) in self.graph[v].iter().enumerate() { if e.cap > 0 && dist[e.to] > dist[v] + e.cost + h[v] - h[e.to] { dist[e.to] = dist[v] + e.cost + h[v] - h[e.to]; self.prev[e.to] = (v, i); que.push((-dist[e.to], e.to)); } } } if dist[t] == inf { return -1; // Cannot add flow anymore } for i in 0..n { h[i] += dist[i]; } // Add flow fully let mut d = f; let mut i = t; while i != s { let (pv, pe) = self.prev[i]; d = std::cmp::min(d, self.graph[pv][pe].cap); i = pv; } f -= d; res += d as Cost * h[t]; i = t; while i != s { let (pv, pe) = self.prev[i]; self.graph[pv][pe].cap -= d; let erev = self.graph[pv][pe].rev; self.graph[i][erev].cap += d; i = pv; } } return res; } } // https://yukicoder.me/problems/no/200 (4) // MCFで、共通部分があるブロック間に辺を張る。容量は1でコストは勝ちなら0,それ以外なら1。 // MCFで流量をNにすれば、 // Tags: min-cost-flow fn main() { let n = getline().trim().parse::().unwrap(); getline(); let mut b = getline().trim().split_whitespace() .map(|x| x.parse::().unwrap()) .collect::>(); b.sort(); b.reverse(); let a = b.len(); getline(); let mut d = getline().trim().split_whitespace() .map(|x| x.parse::().unwrap()) .collect::>(); d.sort(); let c = d.len(); let mut mcf = MinCostFlow::new(2 + 2 * n); for i in 0..n { mcf.add_edge(0, 2 + i, 1, 0); mcf.add_edge(2 + n + i, 1, 1, 0); } let mut frm = vec![]; let mut lat = vec![]; for i in 0..n { frm.push(b[i % a]); lat.push(d[i % c]); } for bl1 in 0..(n + a - 1) / a { let l1 = bl1 * a; let r1 = n.min((bl1 + 1) * a); for bl2 in 0..(n + c - 1) / c { let l2 = bl2 * c; let r2 = n.min((bl2 + 1) * c); if l1.max(l2) >= r1.min(r2) { continue; } for i in l1..r1 { for j in l2..r2 { mcf.add_edge(2 + i, 2 + n + j, 1, if frm[i] > lat[j] { 0 } else { 1 }); } } } } let cost = mcf.min_cost_flow(0, 1, n as isize); println!("{}", n as i64 - cost); }