# input import sys # input = sys.stdin.readline II = lambda : int(input()) MI = lambda : map(int, input().split()) LI = lambda : [int(a) for a in input().split()] SI = lambda : input().rstrip() LLI = lambda n : [[int(a) for a in input().split()] for _ in range(n)] LSI = lambda n : [input().rstrip() for _ in range(n)] MI_1 = lambda : map(lambda x:int(x)-1, input().split()) LI_1 = lambda : [int(a)-1 for a in input().split()] mod = 998244353 inf = 1001001001001001001 ordalp = lambda s : ord(s)-65 if s.isupper() else ord(s)-97 ordallalp = lambda s : ord(s)-39 if s.isupper() else ord(s)-97 yes = lambda : print("Yes") no = lambda : print("No") yn = lambda flag : print("Yes" if flag else "No") prinf = lambda ans : print(ans if ans < 1000001001001001001 else -1) alplow = "abcdefghijklmnopqrstuvwxyz" alpup = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" alpall = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ" URDL = {'U':(-1,0), 'R':(0,1), 'D':(1,0), 'L':(0,-1)} DIR_4 = [[-1,0],[0,1],[1,0],[0,-1]] DIR_8 = [[-1,0],[-1,1],[0,1],[1,1],[1,0],[1,-1],[0,-1],[-1,-1]] DIR_BISHOP = [[-1,1],[1,1],[1,-1],[-1,-1]] prime60 = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59] sys.set_int_max_str_digits(0) # sys.setrecursionlimit(10**6) # import pypyjit # pypyjit.set_param('max_unroll_recursion=-1') from collections import defaultdict,deque from heapq import heappop,heappush from bisect import bisect_left,bisect_right DD = defaultdict BSL = bisect_left BSR = bisect_right p = SI() q = II() n, m = MI() xs = LI() xi = [(x, i) for i, x in enumerate(xs)] xi.sort() if p == "Bob": n, m = m, n """ 自分は長さ n の配列 xs が与えられている 境界がかなり怪しいどうすればいいんだ 考え直しっぽいな 素直に小さい順から探索するほうが筋がいいっぽいど。 回数足りなくて鬱。想定解引かないと回数足りないのしんどい うーん、、、すこしずるしますか? """ k = (n + m) // 2 + 1 nn = 0 mm = 0 for i in range(q): if nn == n: # 返ってきたのを返す x, idx = xi[0] print("share", idx + 1) v = II() print("answer", v) exit() if mm == m: # 答えを返す x, idx = xi[nn + k - 1] print("share", idx + 1) v = II() print("answer", x) exit() if k == 1: # x, idx = xi[nn] # print("share", idx + 1) # v = II() print("answer", min(x, v)) exit() dn = min(n - nn, k // 2) dm = min(m - mm, k // 2) x, idx = xi[nn + dn - 1] print("share", idx + 1) v = II() if x == v: print("answer", x) exit() if x < v: nn += dn k -= dn else: mm += dm k -= dm