#include #include #define rep(i,n) for(int i=0;i P; template ostream& operator<<(ostream& os, const static_modint& a) {os << a.val(); return os;} template ostream& operator<<(ostream& os, const dynamic_modint& a) {os << a.val(); return os;} template istream& operator>>(istream& is, static_modint& a) {long long x; is >> x; a = x; return is;} template istream& operator>>(istream& is, dynamic_modint& a) {long long x; is >> x; a = x; return is;} template istream& operator>>(istream& is, vector& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template ostream& operator<<(ostream& os, const pair& p){os << p.first << ' ' << p.second; return os;} template ostream& operator<<(ostream& os, const vector& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template ostream& operator<<(ostream& os, const vector>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template ostream& operator<<(ostream& os, const set& se){for(T x : se) os << x << " "; os << "\n"; return os;} template ostream& operator<<(ostream& os, const unordered_set& se){for(T x : se) os << x << " "; os << "\n"; return os;} template ostream& operator<<(ostream& os, const atcoder::segtree& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template ostream& operator<<(ostream& os, atcoder::lazy_segtree& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template void chmin(T& a, T b){a = min(a, b);} template void chmax(T& a, T b){a = max(a, b);} int solve(){ int n; cin >> n; n *= 2; vector x(n), y(n); vector c(n); rep(i, n) cin >> x[i] >> y[i] >> c[i]; map mpx, mpy; int totx = 0, toty = 0; rep(i, n){ if(c[i] == 'x'){ mpx[y[i]]++; totx++; } if(c[i] == 'y'){ mpy[x[i]]++; toty++; } } if(totx <= toty){ int ans = totx; for(auto [key, val] : mpy){ ans += val / 2; } if(ans >= n / 2) cout << "Yes\n"; else cout << "No\n"; }else{ int ans = toty; for(auto [key, val] : mpx){ ans += val / 2; } if(ans >= n / 2) cout << "Yes\n"; else cout << "No\n"; } return 0; } int main(){ int t; cin >> t; rep(_, t) solve(); return 0; }