#include #include #define rep(i,n) for(int i=0;i P; template ostream& operator<<(ostream& os, const static_modint& a) {os << a.val(); return os;} template ostream& operator<<(ostream& os, const dynamic_modint& a) {os << a.val(); return os;} template istream& operator>>(istream& is, static_modint& a) {long long x; is >> x; a = x; return is;} template istream& operator>>(istream& is, dynamic_modint& a) {long long x; is >> x; a = x; return is;} template istream& operator>>(istream& is, vector& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template ostream& operator<<(ostream& os, const pair& p){os << p.first << ' ' << p.second; return os;} template ostream& operator<<(ostream& os, const vector& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template ostream& operator<<(ostream& os, const vector>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template ostream& operator<<(ostream& os, const set& se){for(T x : se) os << x << " "; os << "\n"; return os;} template ostream& operator<<(ostream& os, const unordered_set& se){for(T x : se) os << x << " "; os << "\n"; return os;} template ostream& operator<<(ostream& os, const atcoder::segtree& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template ostream& operator<<(ostream& os, atcoder::lazy_segtree& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template void chmin(T& a, T b){a = min(a, b);} template void chmax(T& a, T b){a = max(a, b);} int solve(){ int k; cin >> k; if(k <= 17){ vector a(3); for(int x = 1; x <= k; x++){ if(x <= 2 or x % 2 == 0){ a[2]++; }else{ a[0]++; } } string ans; for(int i = 2; i >= 0; i--){ if(a[i] == 0){ if(ans.size()) ans += '0' + a[i]; }else ans += '0' + a[i]; } cout << ans << "\n"; }else{ if((k - 17) % 9 == 0){ string ans = "908"; rep(i, (k - 17) / 9) ans += '9'; cout << ans << "\n"; }else{ string ans; ans += '0' + (k - 17) % 9; ans += "908"; rep(i, (k - 17) / 9) ans += '9'; cout << ans << "\n"; } } return 0; } int main(){ int t; cin >> t; rep(_, t) solve(); return 0; }