#include #include using namespace std; using namespace atcoder; #define rep(i, n) REP(i, 0, n) #define REP(i, s, e) for (ll i = (s); i < (ll)(e); i++) #define repr(i, n) REPR(i, n, 0) #define REPR(i, s, e) for (ll i = (ll)(s - 1); i >= (ll)(e); i--) #define all(r) r.begin(), r.end() #define rall(r) r.rbegin(), r.rend() typedef long long ll; typedef vector vi; typedef vector vl; template bool chmax(T& a, const U& b) { if (a >= b) return false; a = b; return true; } template bool chmin(T& a, const U& b) { if (a <= b) return false; a = b; return true; } void yes_no(bool f, string yes = "Yes", string no = "No") { cout << (f ? yes : no) << "\n"; } void solve() { int n; cin >> n; dsu uf(n); using D = long double; using P = pair; vector

pos(n); rep(i, n) { int x, y; cin >> x >> y; pos[i] = {x, y}; } D ans = 1; const D eps = 1e-9; rep(i, n) rep(j, i) { D x1 = pos[i].first, y1 = pos[i].second; D x2 = pos[j].first, y2 = pos[j].second; if (hypotl(x1 - x2, y1 - y2) < 10 + eps) { uf.merge(i, j); } } rep(i, n) rep(j, n) if (uf.same(i, j)) { D x1 = pos[i].first, y1 = pos[i].second; D x2 = pos[j].first, y2 = pos[j].second; D d = hypotl(x1 - x2, y1 - y2); chmax(ans, d + 2); } cout << fixed << setprecision(15); cout << ans << "\n"; } int main() { cin.tie(0); ios::sync_with_stdio(false); int t = 1; // cin >> t; rep(ti, t) solve(); return 0; }