#include #include using namespace std; using namespace atcoder; typedef long long int ll; typedef long double ld; typedef vector vi; typedef vector vl; typedef vector vvl; typedef vector vvvl; typedef vector vvvvl; typedef vector vb; typedef vector vvb; typedef vector vvvb; typedef vector vvvvb; typedef pair pl; typedef pair ppl; typedef pair pppl; typedef pair pppppl; #define rep(i,a,b) for(int i=(a);i<(b);i++) #define rrep(i,a,b) for(int i=(b)-1;i>=(a);i--) #define all(a) begin(a),end(a) #define sz(a) (int)(a).size() #define F first #define S second #define bs(A,x) binary_search(all(A),x) #define lb(A,x) (ll)(lower_bound(all(A),x)-A.begin()) #define ub(A,x) (ll)(upper_bound(all(A),x)-A.begin()) #define cou(A,x) (ll)(upper_bound(all(A),x)-lower_bound(all(A),x)) templateusing min_priority_queue=priority_queue,greater>; templatebool chmax(T&a,T b){if(abool chmin(T&a,T b){if(b vm; typedef vector vvm; typedef vector vvvm; typedef vector vvvvm; ostream&operator<<(ostream&os,mint a){os<>(istream&is,mint&a){int x;is>>x;a=mint(x);return is;} //*/ templateostream&operator<<(ostream&os,pairp){os<istream&operator>>(istream&is,pair&p){is>>p.F>>p.S;return is;} templateostream&operator<<(ostream&os,vectorv){rep(i,0,sz(v))os<istream&operator>>(istream&is,vector&v){for(T&in:v)is>>in;return is;} // https://github.com/kth-competitive-programming/kactl/blob/main/content/numerical/Simplex.h typedef vector vi; typedef vector vd; typedef vector vvd; const ld eps=1e-8,inf=1/.0; #define MP make_pair #define ltj(X) if(s==-1||MP(X[j],N[j])eps){ ld*b=D[i].data(),inv2=b[s]*inv; rep(j,0,n+2)b[j]-=a[j]*inv2; b[s]=a[s]*inv2; } rep(j,0,n+2)if(j!=s)D[r][j]*=inv; rep(i,0,m+2)if(i!=r)D[i][s]*=-inv; D[r][s]=inv; swap(B[r],N[s]); } bool simplex(int phase){ int x=m+phase-1; for(;;){ int s=-1; rep(j,0,n+1)if(N[j]!=-phase)ltj(D[x]); if(D[x][s]>=-eps)return true; int r=-1; rep(i,0,m){ if(D[i][s]<=eps)continue; if(r==-1||MP(D[i][n+1]/D[i][s],B[i])sync_with_stdio(0); cin.exceptions(cin.failbit); ll _;cin>>_; while(_--){ ll N,M;cin>>N>>M; vvl A(N,vl(M));cin>>A; vvd X(M+2,vd(N+1)); rep(i,0,N)rep(j,0,M)X[j][i]=A[i][j]; rep(i,0,M)X[i][N]=1; rep(i,0,N)X[M][i]=1,X[M+1][i]=-1; vd y(M+2,11000),z(N+1),x; y[M]=1;y[M+1]=-1;z[N]=1; vector>XT(N+1,vd(M+2)); rep(i,0,N+1)rep(j,0,M+2)XT[i][j]=X[j][i]; ld val=LPSolver(XT,z,y).solve(x); printf("%.20Lf\n",11000-val); } return 0; }