#include using namespace std; #define rep(i, x, limit) for (long long i = (long long)x; i < (long long)limit; i++) #define REP(i, x, limit) for (long long i = (long long)x; i <= (long long)limit; i++) #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define el '\n' #define spa " " #define Yes cout << "Yes" << el #define No cout << "No" << el #define YES cout << "YES" << el #define NO cout << "NO" << el #define inp(x) for(auto &i:x)cin>>i #define eps (1e-10) #define Equals(a,b) (fabs((a) - (b)) < eps ) #define debug(x) cerr << #x << " = " << x << el using ll = long long; using ull = unsigned long long; using i128 = __int128_t; using pii = pair; using pll = pair; using vi = vector; using vl = vector; using vvl = vector>; using vs = vector; using vb = vector; const double pi = 3.141592653589793238; const int inf = 1073741823; const ll infl = 1LL << 60; const string ABC = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; const string abc = "abcdefghijklmnopqrstuvwxyz"; const ll MOD = 998244353; #include using namespace atcoder; using mint = modint998244353; using vm = vector; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); //(n-b)Ck/nCk*kが最大となるkを求める。 //(n-b)!/(k!*(n-b-k)!)/n!*(k!*(n-k)!)*k //(n-b)!*(n-k)!/(n!*(n-b-k)!)*k //(n-b)!/n!*k*(n-k)!/(n-b-k)! //k*(n-k)!/(n-b-k)!が最大となればいい。 //kを1増やすと(k+1)*(n-k-1)!/(n-b-k-1)! int t;cin>>t; while(t--){ ll n,b;cin>>n>>b; cout<