#include <iostream>
using namespace std;
long long ncm[50][50];
int main(){
	int n;	cin>>n;
	if(n>31){
		cout<<"0 0"<<endl;
		return 0;
	}
	ncm[0][0]=1;
	for(int i=0;i<40;i++){
	    for(int j=0;j<=i;j++){
	        ncm[i+1][j]+=ncm[i][j];
	        ncm[i+1][j+1]+=ncm[i][j];
	    }
	}
	long long ret=1;
	//the first answer is 32Cn.
	//the second andswer is 2^32*31C(n-1).
	cout<<ncm[31][n]<<" "<<((1LL<<31)-1)*ncm[30][n-1]<<endl;
	return 0;
}