#![allow(unused_imports, dead_code, unused_macros, unused_variables, non_snake_case, unused_parens)] use proconio::{input,marker::{Bytes, Chars, Usize1,Isize1}}; use std::{ops::*, vec}; use std::cmp::*; use std::mem::swap; use std::collections::*; const MOD:u64 = 1_000_000_007; const INF:i64 = 0x3fff_ffff_ffff_ffff; const YES:&str="Yes";const NO:&str="No";macro_rules!yesno{($var:expr) => {if $var{println!("{}",YES);}else{println!("{}",NO);}}} macro_rules! min {($a:expr $(,)*) => {{$a}};($a:expr, $b:expr $(,)*) => {{std::cmp::min($a, $b)}};($a:expr, $($rest:expr),+ $(,)*) => {{std::cmp::min($a, min!($($rest),+))}};} macro_rules! max {($a:expr $(,)*) => {{$a}};($a:expr, $b:expr $(,)*) => {{std::cmp::max($a, $b)}};($a:expr, $($rest:expr),+ $(,)*) => {{std::cmp::max($a, max!($($rest),+))}};} macro_rules! chmin {($base:expr, $($cmps:expr),+ $(,)*) => {{let cmp_min = min!($($cmps),+);if $base > cmp_min {$base = cmp_min;true} else {false}}};} macro_rules! chmax {($base:expr, $($cmps:expr),+ $(,)*) => {{let cmp_max = max!($($cmps),+);if $base < cmp_max {$base = cmp_max;true} else {false}}};} macro_rules! mulvec {($x:expr; $s:expr) => {vec![$x; $s]};($x:expr; $s0:expr; $( $s:expr );+) => {mulvec![vec![$x; $s0]; $( $s );+ ]};} macro_rules! outputln {($var:expr)=>{println!("{}",$var)};($var:expr,$($vars:expr),+)=>{print!("{} ",$var);outputln!($($vars),+);};} macro_rules! debug {($($a:expr),* $(,)*) => {eprintln!(concat!($("| ",stringify!($a), "={:?} "),*, "|"),$(&$a),*);};} fn solve() { input! { mut R: i64, mut P: i64, mut Q: i64, mut A: i64, mut B: i64, mut C: i64, mut D: i64, } let mut ans = 0; let mut ABC = vec![A,B,C]; ABC.sort(); A = ABC[0]; B = ABC[1]; C = ABC[2]; // まずルーマニア人を最大限作る let d = min!(A,B,C, R/P); ans += d; A -= d; B -= d; C -= d; R -= d*P; // A,B,Cのうち2番目の人数を一番少ない人数に合わせる。 let d = min!(B - A, D, R / (P+Q)); ans += d; B -= d; C -= d; D -= d; R -= d*(P+Q); // DをA,Bに分配 let d = min!(C - B, D/2, R / (P+Q+Q)); ans += d; C -= d; D -= d*2; R -= d*(P+Q+Q); // Dを均等に配分 let d = min!(D / 3, R / (P + Q*3)); ans += d; D -= d*3; R -= d*(P+Q*3); // CをAに配分 let d = min!(B-A, C-B, R / (P+Q)); ans += d; C -= d*2; B -= d; R -= d * (P+Q); // CをA,Bに配分 let d = min!((C-A)/2, R / (P+Q*2)); ans += d; C -= d*3; R -= d * (P+Q*2); debug!((A,B,C,D), R); outputln!(ans); } fn main() { std::thread::Builder::new() .stack_size(128 * 1024 * 1024) .spawn(|| solve()).unwrap() .join().unwrap(); }