#include <algorithm>
#include <atcoder/all>
#include <bitset>
#include <cassert>
#include <cmath>
#include <ctime>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using namespace atcoder;
typedef long long ll;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--)
#define repk(i, k, n) for (int i = k; i < (int)(n); i++)
#define all(v) v.begin(), v.end()
#define mod1 1000000007
#define mod2 998244353
#define mod3 100000007
#define vi vector<int>
#define vs vector<string>
#define vc vector<char>
#define vl vector<ll>
#define vb vector<bool>
#define vvi vector<vector<int>>
#define vvc vector<vector<char>>
#define vvl vector<vector<ll>>
#define vvb vector<vector<bool>>
#define vvvi vector<vector<vector<int>>>
#define vvvl vector<vector<vector<ll>>>
#define pii pair<int, int>
#define pil pair<int, ll>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define vpii vector<pair<int, int>>
#define vpll vector<pair<ll, ll>>
#define vvpii vector<vector<pair<int, int>>>
#define vvpll vector<vector<pair<ll, ll>>>

template <typename T>
void debug(T e) {
    cerr << e << endl;
}

template <typename T>
void debug(vector<T> &v) {
    rep(i, v.size()) { cerr << v[i] << " "; }
    cerr << endl;
}

template <typename T>
void debug(vector<vector<T>> &v) {
    rep(i, v.size()) {
        rep(j, v[i].size()) { cerr << v[i][j] << " "; }
        cerr << endl;
    }
}

template <typename T>
void debug(vector<pair<T, T>> &v) {
    rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; }
}

template <typename T>
void debug(set<T> &st) {
    for (auto itr = st.begin(); itr != st.end(); itr++) {
        cerr << *itr << " ";
    }
    cerr << endl;
}

template <typename T>
void debug(multiset<T> &ms) {
    for (auto itr = ms.begin(); itr != ms.end(); itr++) {
        cerr << *itr << " ";
    }
    cerr << endl;
}

template <typename T>
void debug(map<T, T> &mp) {
    for (auto itr = mp.begin(); itr != mp.end(); itr++) {
        cerr << itr->first << " " << itr->second << endl;
    }
}

void debug_out() { cerr << endl; }

template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
    cerr << H << " ";
    debug_out(T...);
}

using mint = modint998244353;

void debug_mint1(vector<mint> &vec) {
    for (int i = 0; i < vec.size(); i++) {
        cerr << vec[i].val() << " ";
    }
    cerr << endl;
}

void debug_mint2(vector<vector<mint>> &vec) {
    for (int i = 0; i < vec.size(); i++) {
        for (int j = 0; j < vec[i].size(); j++) {
            cerr << vec[i][j].val() << " ";
        }
        cerr << endl;
    }
}

int main() {
    ll N, K;
    cin >> N >> K;
    // 大前提：何個あるとアウトか？
    // K = 1 は 1 個でアウト
    // K = N は N 個でアウト
    // すなわち空白マスの個数が大事！
    // 空白マス最小何個で埋め尽くせる？
    ll vacant = N / K;
    ll needs = N - vacant + 1;
    debug(needs);

    vector<ll> A(N);
    rep(i, N) cin >> A[i];
    // 素数でのみ割ることにする

    ll L = 1000000;
    vector<bool> isprime(L + 1, true);
    for (ll i = 2; i <= L; i++){
        if (isprime[i]){
            for (ll j = 2; j * i <= L; j++){
                isprime[i * j] = false;
            }
        }
    }
    vector<ll> primes;
    for (ll i = 2; i <= 1000; i++){
        if (isprime[i]) primes.push_back(i);
    }
    vector<ll> B(N);
    rep(i, N) B[i] = A[i];

    mint ans = mint(1);
    // prime を求めていく
    for (ll p: primes){
        vector<ll> cnts(102, 0);
        for (ll i = 0; i < N; i++){
            ll cnt = 0;
            while (true){
                if (B[i] % p != 0) break;
                B[i] /= p;
                cnt++;
            }
            cnts[cnt]++;
        }
        ll now_sum = 0;
        for (ll j = 101; j >= 0; j--){
            now_sum += cnts[j];
            if (now_sum >= needs){
                ans *= mint(p).pow(j);
                break;
            }
        }
        // debug_out(p, ans.val());
    }
    // あとは高々 1 個である
    vector<ll> l_cnts(L + 1, 0);
    for (ll i = 0; i < N; i++){
        if (B[i] != 1) l_cnts[B[i]]++;
    }
    for (ll i = 1001; i <= L; i++){
        if (l_cnts[i] >= needs){
            ans *= mint(i);
        }
    }
    cout << ans.val() << endl;
}