#include using namespace std; using ll = long long; using ld = long double; using pll = array; using vl = vector; template using vec = vector; template using vv = vec>; template using vvv = vv>; template using minpq = priority_queue, greater>; #define all(a) (a).begin(),(a).end() #define rep(i, n) for (ll i = 0; i < (n); ++i) #define reps(i, l, r) for(ll i = (l); i < (r); ++i) #define rrep(i, l, r) for(ll i = (r)-1; i >= (l); --i) #define sz(x) (ll) (x).size() template bool chmax(T &a, const T& b) { return a < b ? a = b, true : false; } template bool chmin(T &a, const T& b) { return a > b ? a = b, true : false; } const ll mod = 998244353; // 1000000007; struct mint { ll x; mint(ll y = 0) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {} mint &operator+=(const mint &p) { if ((x += p.x) >= mod) x -= mod; return *this; } mint &operator-=(const mint &p) { if ((x += mod - p.x) >= mod) x -= mod; return *this; } mint &operator*=(const mint &p) { x = (ll)(1ll * x * p.x % mod); return *this; } mint &operator/=(const mint &p) { *this *= p.inv(); return *this; } mint operator-() const { return mint(-x); } mint operator+(const mint &p) const { return mint(*this) += p; } mint operator-(const mint &p) const { return mint(*this) -= p; } mint operator*(const mint &p) const { return mint(*this) *= p; } mint operator/(const mint &p) const { return mint(*this) /= p; } bool operator==(const mint &p) const { return x == p.x; } bool operator!=(const mint &p) const { return x != p.x; } friend ostream &operator<<(ostream &os, const mint &p) { return os << p.x; } friend istream &operator>>(istream &is, mint &a) { ll t; is >> t; a = mint(t); return (is); } mint inv() const { return pow(mod - 2); } mint pow(ll n) const { mint ret(1), mul(x); while (n > 0) { if (n & 1) ret *= mul; mul *= mul; n >>= 1; } return ret; } }; void solve(){ ll N; cin >> N; vv a(N, vl(N)); rep(i, N){ rep(k, N) cin >> a[i][k]; } ll sum = 0; rep(i, N){ rep(k, N) sum += a[i][k]; } if(sum % N != 0){ cout << -1 << endl; return; } vv ans(N, vl(N, -1)); ll L = 0, R = 0; rep(i, N-1){ vl v = a[i]; v[0] += L, v[N-1] += R; vl s(N+1, 0); rep(k, N) s[k+1] = s[k] + v[k]; vl idx(N, -1); idx[0] = 0; ll l, r; rep(k, N){ ll x = s[k+1] % N; if(x == 0){ l = 0, r = k+1; break; } if(idx[x] == -1) idx[x] = k+1; else{ l = idx[x], r = k+1; break; } } reps(t, l, r) ans[i][t] = i+1; if(l == 0) L = 0; else L += s[l]; if(r == N) R = 0; else R += s[N] - s[r]; } ll cL = N, cR = N; rep(k, N) ans[N-1][k] = N; rrep(i, 0, N-1){ if(ans[i][0] != -1) cL = ans[i][0]; else{ rep(k, N){ if(ans[i][k] == -1) ans[i][k] = cL; else break; } } if(ans[i][N-1] != -1) cR = ans[i][N-1]; else{ rrep(k, 0, N){ if(ans[i][k] == -1) ans[i][k] = cR; else break; } } } rep(i, N){ rep(k, N){ cout << ans[i][k] << " \n"[k == N-1]; } } return; } int main(){ cin.tie(nullptr); ios_base::sync_with_stdio(false); cout << fixed << setprecision(20); int t = 1; cin >> t; while(t--){ solve(); } }