#include #define rep(i, p, n) for (ll i = p; i < (ll)(n); i++) #define rep2(i, p, n) for (ll i = p; i >= (ll)(n); i--) using namespace std; using ll = long long; using ld = long double; const double pi = 3.141592653589793; const long long inf = 2 * 1e9; const long long linf = (1LL << 61); const ll mod1 = 1000000007; const ll mod2 = 998244353; template inline bool chmax(T &a, T b) { if (a < b) { a = b; return 1; } return 0; } template inline bool chmin(T &a, T b) { if (a > b) { a = b; return 1; } return 0; } template using priority_queue_rev = priority_queue, greater>; #include using namespace atcoder; using mint1 = modint1000000007; using mint2 = modint998244353; vector> base = {{0, -1}, {-1, 0}, {0, 1}, {1, 0}}; void solve() { ll n, k; cin >> n >> k; if (k == 0) { cout << -1 << endl; return; } ll ans[n][n]; ll p = n * n - k + 1; rep(i, 0, n) { rep(j, 0, i) { ans[i][j] = p; p++; if (p == n * n + 1) { p = 1; } } rep(j, 0, i + 1) { ans[j][i] = p; p++; if (p == n * n + 1) { p = 1; } } } rep(i, 0, n) { rep(j, 0, n) { cout << ans[i][j] << " "; } cout << endl; } } int main() { ////////////////// ios::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); ////////////////// // ll T; // cin >> T; // while (T--) solve(); return 0; }