#include #include using namespace std; using namespace atcoder; #define rep(i, n) REP(i, 0, n) #define REP(i, s, e) for (ll i = (s); i < (ll)(e); i++) #define repr(i, n) REPR(i, n, 0) #define REPR(i, s, e) for (ll i = (ll)(s - 1); i >= (ll)(e); i--) #define all(r) r.begin(), r.end() #define rall(r) r.rbegin(), r.rend() typedef long long ll; typedef vector vi; typedef vector vl; template T chmax(T& a, const U& b) { if (a >= b) return false; a = b; return true; } template T chmin(T& a, const U& b) { if (a <= b) return false; a = b; return true; } void yes_no(bool f, string yes = "Yes", string no = "No") { cout << (f ? yes : no) << "\n"; } void solve() { vi a(3); rep(i, 3) cin >> a[i]; string s; cin >> s; map mp{{'G', 0}, {'C', 1}, {'P', 2}}; vector dp(a[0] + 1, vector(a[1] + 1, vector(a[2] + 1, -1e9))); dp[a[0]][a[1]][a[2]] = 0; repr(i, a[0] + 1) repr(j, a[1] + 1) repr(k, a[2] + 1) { int x = a[0] + a[1] + a[2] - (i + j + k); if (x == s.size()) continue; auto c = s[x]; if (i > 0) { if (mp[c] == 1) chmax(dp[i - 1][j][k], dp[i][j][k] + 3); else if (mp[c] == 0) chmax(dp[i - 1][j][k], dp[i][j][k] + 1); else chmax(dp[i - 1][j][k], dp[i][j][k]); } if (j > 0) { if (mp[c] == 2) chmax(dp[i][j - 1][k], dp[i][j][k] + 3); else if (mp[c] == 1) chmax(dp[i][j - 1][k], dp[i][j][k] + 1); else chmax(dp[i][j - 1][k], dp[i][j][k]); } if (k > 0) { if (mp[c] == 0) chmax(dp[i][j][k - 1], dp[i][j][k] + 3); else if (mp[c] == 2) chmax(dp[i][j][k - 1], dp[i][j][k] + 1); else chmax(dp[i][j][k - 1], dp[i][j][k]); } } int ans = dp[0][0][0]; cout << ans << "\n"; } int main() { cin.tie(0); ios::sync_with_stdio(false); int t = 1; // multi-testcase // cin >> t; rep(ti, t) solve(); return 0; }