#line 1 "f.cpp"
#include <bits/stdc++.h>
#line 3 "f.cpp"
using namespace std;
using ll=long long;
const ll ILL=2167167167167167167;
const int INF=2100000000;
#define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++)
#define all(p) p.begin(),p.end()
template<class T> using pq_ = priority_queue<T, vector<T>, greater<T>>;
template<class T> int LB(vector<T> &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();}
template<class T> int UB(vector<T> &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();}
template<class T> bool chmin(T &a,T b){if(b<a){a=b;return 1;}else return 0;}
template<class T> bool chmax(T &a,T b){if(a<b){a=b;return 1;}else return 0;}
template<class T> void So(vector<T> &v) {sort(v.begin(),v.end());}
template<class T> void Sore(vector<T> &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});}
bool yneos(bool a,bool upp=false){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;}
template<class T> void vec_out(vector<T> &p,int ty=0){
    if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'<<p[i]<<'"';}cout<<"}\n";}
    else{if(ty==1){cout<<p.size()<<"\n";}for(int i=0;i<(int)(p.size());i++){if(i) cout<<" ";cout<<p[i];}cout<<"\n";}}
template<class T> T vec_min(vector<T> &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;}
template<class T> T vec_max(vector<T> &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;}
template<class T> T vec_sum(vector<T> &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;}
int pop_count(long long a){int res=0;while(a){res+=(int)(a&1),a>>=1;}return res;}
template<class T> T square(T a){return a * a;}

#line 2 "/Users/Shared/po167_library/fps/FPS_composition.hpp"
#include <atcoder/convolution>

namespace po167{
// n = |g|
// return f(g(x))
// https://maspypy.com/fps-合成・逆関数の解説（2）転置原理による合成ア
template<class T>
std::vector<T> FPS_comp(std::vector<T> f, std::vector<T> g){
    assert(g[0] == 0);
    auto rec = [&](auto rec, int n, int k, std::vector<T> Q) -> std::vector<T> {
        if (n == 1){
            std::vector<T> p(2 * k);
            std::reverse(f.begin(), f.end());
            for (int i = 0; i < k; i++) p[2 * i] = f[i];
            return p;
        }
        std::vector<T> nxt_Q(2 * n * k);
        for (int i = 0; i < n * k; i++) nxt_Q[n * k + i] += Q[i * 2] * 2;
        Q.resize(4 * n * k);
        atcoder::internal::butterfly(Q);
        // Q(-x)
        std::vector<T> R(4 * n * k);
        for (int i = 0; i < 2 * n * k; i++){
            R[i * 2] = Q[i * 2 + 1];
            R[i * 2 + 1] = Q[i * 2];
        }
        T iz = (T)(1) / (T)(4 * n * k);
        for (int i = 0; i < 4 * n * k; i++) Q[i] *= R[i];
        for (int i = 0; i < 2 * n * k; i++) Q[i] = Q[i * 2];
        Q.resize(2 * n * k);
        atcoder::internal::butterfly_inv(Q);
        for (int i = 0; i < 2 * n * k; i++) nxt_Q[i] += Q[i] * iz * 2;
        for (int j = 0; j < 2 * k; j++) for (int i = n / 2; i < n; i++){
            nxt_Q[n * j + i] = 0;
        }
        std::vector<T> pq = rec(rec, n / 2, k * 2, nxt_Q);
        std::vector<T> p(2 * n * k);
        for (int j = 0; j < 2 * k; j++) for (int i = n / 2; i < n; i++){
            pq[n * j + i] = 0;
        }
        for (int i = 0; i < n * k; i++) p[i * 2 + 1] += pq[n * k + i];
        std::reverse(pq.begin(), pq.end());
        atcoder::internal::butterfly(pq);
        pq.resize(4 * n * k);
        for (int i = 2 * n * k - 1; i >= 0; i--){
            pq[i * 2 + 1] = pq[i];
            pq[i * 2] = pq[i];
        }
        for (int i = 0; i < 4 * n * k; i++) pq[i] *= R[i];
        atcoder::internal::butterfly_inv(pq);
        for (int i = 0; i < 2 * n * k; i++) p[i] += pq[4 * n * k - 1 - i] * iz;
        return p;
    };
    int N = (int)g.size();
    int n = 1;
    while (n < N) n *= 2;
    f.resize(n, 0);
    g.resize(n, 0);
    std::vector<T> Q(2 * n);
    for (int i = 0; i < n; i++) Q[i] = -g[i];
    auto p = rec(rec, n, 1, Q);
    std::vector<T> res(n);
    for (int i = 0; i < n; i++) res[i] = p[i];
    std::reverse(res.begin(), res.end());
    res.resize(N);
    return res;
}
}
#line 27 "f.cpp"
using mint = atcoder::modint998244353;
#line 2 "/Users/Shared/po167_library/math/Binomial.hpp"

#line 5 "/Users/Shared/po167_library/math/Binomial.hpp"

namespace po167{
template<class T>
struct Binomial{
    std::vector<T> fact_vec, fact_inv_vec;
    void extend(int m = -1){
        int n = fact_vec.size();
        if (m == -1) m = n * 2;
        if (n >= m) return;
        fact_vec.resize(m);
        fact_inv_vec.resize(m);
        for (int i = n; i < m; i++){
            fact_vec[i] = fact_vec[i - 1] * T(i);
        }
        fact_inv_vec[m - 1] = T(1) / fact_vec[m - 1];
        for (int i = m - 1; i > n; i--){
            fact_inv_vec[i - 1] = fact_inv_vec[i] * T(i);
        }
    }
    Binomial(int MAX = 0){
        fact_vec.resize(1, T(1));
        fact_inv_vec.resize(1, T(1));
        extend(MAX + 1);
    }

    T fact(int i){
        if (i < 0) return 0;
        while (int(fact_vec.size()) <= i) extend();
        return fact_vec[i];
    }
    T invfact(int i){
        if (i < 0) return 0;
        while (int(fact_inv_vec.size()) <= i) extend();
        return fact_inv_vec[i];
    }
    T C(int a, int b){
        if (a < b || b < 0) return 0;
        return fact(a) * invfact(b) * invfact(a - b);
    }
    T invC(int a, int b){
        if (a < b || b < 0) return 0;
        return fact(b) * fact(a - b) *invfact(a);
    }
    T P(int a, int b){
        if (a < b || b < 0) return 0;
        return fact(a) * invfact(a - b);
    }
    T inv(int a){
        if (a < 0) return inv(-a) * T(-1);
        if (a == 0) return 1;
        return fact(a - 1) * invfact(a);
    }
    T Catalan(int n){
        if (n < 0) return 0;
        return fact(2 * n) * invfact(n + 1) * invfact(n);
    }
    T narayana(int n, int k){
        if (n <= 0 || n < k || k < 1) return 0;
        return C(n, k) *  C(n, k - 1) * inv(n);
    }
    T Catalan_pow(int n,int d){
        if (n < 0 || d < 0) return 0;
        if (d == 0){
            if (n == 0) return 1;
            return 0;
        }
        return T(d) * inv(d + n) * C(2 * n + d - 1, n);
    }
    // retrun [x^a] 1/(1-x)^b
    T ruiseki(int a,int b){
        if (a < 0 || b < 0) return 0;
        if (a == 0){
            return 1;
        }
        return C(a + b - 1, b - 1);
    }
    // (a, b) -> (c, d)
    // always x + e >= y
    T mirror(int a, int b, int c, int d, int e = 0){
        if (a + e < b || c + e < d) return 0;
        if (a > c || b > d) return 0;
        a += e;
        c += e;
        return C(c + d - a - b, c - a) - C(c + d - a - b, c - b + 1); 
    }
    // return sum_{i = 0, ... , a} sum_{j = 0, ... , b} C(i + j, i)
    // return C(a + b + 2, a + 1) - 1;
    T gird_sum(int a, int b){
        if (a < 0 || b < 0) return 0;
        return C(a + b + 2, a + 1) - 1;
    }
    // return sum_{i = a, ..., b - 1} sum_{j = c, ... , d - 1} C(i + j, i)
    // AGC 018 E
    T gird_sum_2(int a, int b, int c, int d){
        if (a >= b || c >= d) return 0;
        a--, b--, c--, d--;
        return gird_sum(a, c) - gird_sum(a, d) - gird_sum(b, c) + gird_sum(b, d);
    }

    // the number of diagonal dissections of a convex n-gon into k+1 regions.
    // OEIS A033282
    // AGC065D
    T diagonal(int n, int k){
        if (n <= 2 || n - 3 < k || k < 0) return 0;
        return C(n - 3, k) * C(n + k - 1, k) * inv(k + 1);
    }
};
}
#line 29 "f.cpp"

void solve();
// DEAR MYSTERIES / TOMOO
int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    int t = 1;
    // cin >> t;
    rep(i, 0, t) solve();
}

void solve(){
    po167::Binomial<mint> table;
    ll N, M;
    int K;
    cin >> N >> M >> K;
    // 指定された x 個が入っている
    vector<mint> q(K + 1);
    /*{
        vector<mint> tmp(N + 1);
        tmp[0] = 1;
        rep(i, 0, N) {
            tmp[i + 1] = tmp[i] * M;
        }
        rep(j, 0, K + 1) {
            q[j] = tmp[N] * table.C(M, j);
            vector<mint> tmp2(N + 1);
            rep(i, 0, N) tmp2[i + 1] += tmp[i] * (j + 1);
            rep(i, 0, N) tmp2[i + 1] += tmp2[i] * (M - j - 1);
            swap(tmp, tmp2);
        }
    }*/
    rep(i, 0, K + 1) {
        q[i] = (mint(M - i)).pow(N);
    }
    {
        vector<mint> to(K + 1);
        rep(i, 0, K + 1) {
            q[i] *= table.invfact(i) * (i & 1 ? -1 : 1);
            to[i] = table.invfact(i);
        }
        auto tmp = atcoder::convolution(to, q);
        mint tmp2 = 1;
        rep(i, 0, K + 1) {
            q[i] = tmp[i] * tmp2;
            tmp2 *= M - i;
        }
    }
    vector<mint> ans(K + 1);
    /*// a 個の積
    rep(a, 0, K + 1) {
        // pow b
        rep(b, a, K + 1) {
            {
                vector<mint> tmp(b + 1);
                tmp[0] = 1;
                rep(i, 0, b) {
                    tmp[i + 1] = tmp[i] * a;
                }
                rep(j, 0, a) {
                    vector<mint> tmp2(b + 1);
                    rep(i, 0, b) tmp2[i + 1] += tmp[i] * (j + 1);
                    rep(i, 0, b) tmp2[i + 1] += tmp2[i] * (a - j - 1);
                    swap(tmp, tmp2);
                }
                mint val = tmp[b];
                ans[b] += val * q[a];
            }
        }
    }*/
    vector<mint> e(K + 1);
    rep(i, 1, K + 1) e[i] = table.invfact(i);
    ans = po167::FPS_comp(q, e);
    rep(i, 1, K + 1) {
        ans[i] *= table.fact(i);
        cout << ans[i].val() << "\n";
    }
}

/*
 * S(n, k) を n 個の区別できる要素を k 個の区別できないグループに分けることを考える
 * このとき、
 * S(n, k) * x^{n}/n! = (e^{x} - 1)^{k} / k!
 * 本当は、S(n, k) ではなくて、
 * T(n, k) = S(n, k) * P(M, k) なので
 * T(n, k) * x^{n} / n! = (e^{x} - 1)^{k} / k! * M! / (M - k)!
 *                      = (e^{x} - 1)^{k} * Binom(M, k)
 * うーん
 * 指定された x 個が入っているかを考える
 * pow k で、x 個の積になっているものを考える
 *
 *
 *
 */