using System;
using static System.Console;
using System.Linq;
using System.Collections.Generic;

class Program
{
    static int NN => int.Parse(ReadLine());
    static int[] NList => ReadLine().Split().Select(int.Parse).ToArray();
    static char[][] SList(long n) => Enumerable.Repeat(0, (int)n).Select(_ => ReadLine().ToCharArray()).ToArray();
    public static void Main()
    {
        Solve();
    }
    static void Solve()
    {
        var t = NN;
        var ans = new bool[t];
        for (var u = 0; u < t; ++u)
        {
            var c = NList;
            ans[u] = Kado(c[0], c[1], c[2], c[3], c[4], c[5]);
        }
        WriteLine(string.Join("\n", ans.Select(f => f ? "YES" : "NO")));
    }
    static bool Kado(int a, int b, int c, int x, int y, int z)
    {
        if ((a < b && b > c) || (a > b && b < c)) return true;
        var ae = a + x * 3000;
        var be = b + y * 3000;
        var ce = c + z * 3000;
        if ((ae < be && be > ce) || (ae > be && be < ce)) return true;
        var abeq = EqTime(a, b, x, y);
        var bceq = EqTime(b, c, y, z);
        var aceq = EqTime(a, c, x, z);
        if (abeq.pa == 0 || bceq.pa == 0 || aceq.pa == 0) return false;
        if (abeq.ch <= 0 && bceq.ch <= 0)
        {
            return false;
        }
        if (abeq.ch == bceq.ch && abeq.pa == bceq.pa)
        {
            return false;
        }
        return true;
    }
    // aとbが同じになる時刻を有理数で返す
    static (int ch, int pa) EqTime(int a, int b, int x, int y)
    {
        if (a == b && x == y) return (1, 0);
        if (a == b) return (0, 1);
        if (x == y) return (-1, 1);
        var ch = b - a;
        var pa = x - y;
        if (pa < 0)
        {
            ch = -ch;
            pa = -pa;
        }
        var gcd = GCD(Math.Abs(ch), pa);
        return (ch / gcd, pa / gcd);
    }
    static int GCD(int a, int b)
    {
        if (a < b) return GCD(b, a);
        if (a % b == 0) return b;
        return GCD(b, a % b);
    }
}