#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using namespace atcoder; typedef long long ll; #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--) #define repk(i, k, n) for (int i = k; i < (int)(n); i++) #define all(v) v.begin(), v.end() #define mod1 1000000007 #define mod2 998244353 #define mod3 100000007 #define vi vector #define vs vector #define vc vector #define vl vector #define vb vector #define vvi vector> #define vvc vector> #define vvl vector> #define vvb vector> #define vvvi vector>> #define vvvl vector>> #define pii pair #define pil pair #define pli pair #define pll pair #define vpii vector> #define vpll vector> #define vvpii vector>> #define vvpll vector>> template void debug(T e) { cerr << e << endl; } template void debug(vector &v) { rep(i, v.size()) { cerr << v[i] << " "; } cerr << endl; } template void debug(vector> &v) { rep(i, v.size()) { rep(j, v[i].size()) { cerr << v[i][j] << " "; } cerr << endl; } } template void debug(vector> &v) { rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; } } template void debug(set &st) { for (auto itr = st.begin(); itr != st.end(); itr++) { cerr << *itr << " "; } cerr << endl; } template void debug(multiset &ms) { for (auto itr = ms.begin(); itr != ms.end(); itr++) { cerr << *itr << " "; } cerr << endl; } template void debug(map &mp) { for (auto itr = mp.begin(); itr != mp.end(); itr++) { cerr << itr->first << " " << itr->second << endl; } } void debug_out() { cerr << endl; } template void debug_out(Head H, Tail... T) { cerr << H << " "; debug_out(T...); } using mint = modint998244353; void debug_mint1(vector &vec) { for (int i = 0; i < vec.size(); i++) { cerr << vec[i].val() << " "; } cerr << endl; } void debug_mint2(vector> &vec) { for (int i = 0; i < vec.size(); i++) { for (int j = 0; j < vec[i].size(); j++) { cerr << vec[i][j].val() << " "; } cerr << endl; } } int main() { ll T; cin >> T; ll L = 1000000; vector dp1(L + 1); // 対称性あり vector dp2(L + 1); // 対称性なし dp1[0] = mint(1); dp1[1] = mint(1); for (ll i = 2; i <= L; i++){ // 同一のラベルからなるものの、同一の箇所をつなぐと対称のグラフが作れる // そうでない場合は対称性のないグラフになる // エスパー:対称性はあっても高々 1 個なのでは? と思ってしまう mint cnt_v1 = mint(2).pow(i - 2); mint cnt_v2 = mint(2).pow(i - 1); mint n1 = cnt_v1; mint n2 = (cnt_v1 * (cnt_v1 - 1)) / mint(2); mint n3 = cnt_v1 * cnt_v1 * (dp1[i - 1] - 1); mint n4 = cnt_v1 * cnt_v2 * dp2[i - 1]; dp1[i] = n1; dp2[i] = n2 + n3 + n4; } while (T--){ ll N; cin >> N; cout << (dp1[N] + dp2[N]).val() << "\n"; } }