#include #include using namespace std; using namespace atcoder; #define rep(i, n) REP(i, 0, n) #define REP(i, s, e) for (ll i = (s); i < (ll)(e); i++) #define repr(i, n) REPR(i, n, 0) #define REPR(i, s, e) for (ll i = (ll)(s - 1); i >= (ll)(e); i--) #define all(r) r.begin(), r.end() #define rall(r) r.rbegin(), r.rend() typedef long long ll; typedef vector vi; typedef vector vl; template bool chmax(T& a, const U& b) { if (a >= b) return false; a = b; return true; } template bool chmin(T& a, const U& b) { if (a <= b) return false; a = b; return true; } void yes_no(bool f, string yes = "Yes", string no = "No") { cout << (f ? yes : no) << "\n"; } struct Sieve { vector primes; vector _isPrime; vector prime_factor_num; // soinsuu no kosuu Sieve(int n) : _isPrime(n + 1, 1), prime_factor_num(n + 1, 0) { buildPrimes(); } void buildPrimes() { _isPrime[0] = _isPrime[1] = 0; int n = _isPrime.size(); REP(i, 2, n) { if (_isPrime[i]) { primes.push_back(i); prime_factor_num[i] = 1; for (int j = i + i; j < n; j += i) _isPrime[j] = 0, prime_factor_num[j]++; } } } bool isPrime(int i) { return _isPrime[i]; } }; void solve() { int k, n; cin >> k >> n; Sieve sieve(n + 10); deque primes(all(sieve.primes)); while (primes.front() < k) primes.pop_front(); while (primes.back() > n) primes.pop_back(); auto hash = [&](auto self, ll x) -> ll { if (x < 10) return x; ll nxt = 0; while (x > 0) { nxt += x % 10; x /= 10; } return self(self, nxt); }; ll ans = primes.front(); ll len = 1; map mp; int r = 0; auto init_state = [&](int l) { r = l; }; auto judge_r = [&](int l, int r) { return mp[hash(hash, primes[r])] == 0; }; auto add_r = [&](int r) { mp[hash(hash, primes[r])]++; }; auto update = [&](int l, int r) { if (r - l >= len) { len = r - l; ans = primes[l]; } }; auto erace_l = [&](int l) { mp[hash(hash, primes[l])]--; }; rep(l, primes.size()) { if (r < l) init_state(l); while (r < primes.size() && judge_r(l, r)) { add_r(r); r++; } update(l, r); erace_l(l); } cout << ans << "\n"; } int main() { cin.tie(0); ios::sync_with_stdio(false); int t = 1; // multi-testcase // cin >> t; rep(ti, t) solve(); return 0; }