#include #include #include using namespace std; using ll = long long; ll modpow(ll a, ll b, ll p){ a%=p; ll ans=1; while(b>0){ if(b%2==1) ans=(ans*a)%p; b/=2; a=(a*a)%p; } return ans; } int main(void){ ll n, l; cin >> n >> l; ll b=(n+l-1)/l, mod=998244353; ll ans=modpow(2, b, mod)-1; cout << (ans+mod)%mod << endl; return 0; }