char s[100010];
n,i,t,ans,c,c3;
inv9[]={0,1,5,0,7,2,0,4,8};
f3(n){int i=0;for(;n&&n%3==0;n/=3)i++;return i;}
g3(n){for(;n&&n%3==0;n/=3);return n;}
main(){
	for(gets(s);gets(s);){
		n=strlen(s)-1;
		t=ans=c3=0,c=1;
		for(i=0;i<=n;i++){
			t+=s[i]-48;
			ans+=c*(c3?c3==1?3:0:1)*(s[i]-48)%9;
			c3+=f3(n-i)-f3(i+1);
			c=(c*g3(n-i)*inv9[g3(i+1)%9])%9;
		}
		printf("%d\n",ans%9?:t?9:0);
	}
}