#pragma GCC optimize ("O3")
// #pragma GCC optimize ("O2") 以下で自動ベクトル化を行う場合は、#pragma GCC optimize ("tree-vectorize") も合わせて記述してください。
#pragma GCC target ("avx") // ターゲットの変更 sse4, avx, avx2 など
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair< int, int > pii;
typedef vector< int > vi;
typedef vector< vi > vvi;
typedef vector< ll > vl;
typedef vector< vl > vvl;
typedef vector< pii > vp;
typedef vector< vp > vvp;
typedef vector< string > vs;
typedef vector< double > vd;
typedef vector< vd > vvd;

template< class T1, class T2 >
int upmin( T1 &x, T2 v ){
  if( x > v ){
    x = v;
    return 1;
  }
  return 0;
}

template< class T1, class T2 >
int upmax( T1 &x, T2 v ){
  if( x < v ){
    x = v;
    return 1;
  }
  return 0;
}

const int INF = 0x3f3f3f3f;
const string msg[] = { "NO", "YES" };
const int dx[] = { 0, 1, 0, -1 };
const int dy[] = { 1, 0, -1, 0 };

int N, V, Ox, Oy;
vvi L;

void init(){
  cin >> N >> V >> Ox >> Oy;
  L = vvi( N, vi( N ) );
  for( int i = 0; i < N; ++i )
    for( int j = 0; j < N; ++j )
      cin >> L[ i ][ j ]; 
}

typedef vector< vvi > vvvi;
typedef vector< vvvi > vvvvi;
vvvvi dp;

int in_range( int n, int x, int y ){
  return 0 <= x and x < n and 0 <= y and y < n;
}

void preprocess(){
  if( V <= L[ 0 ][ 0 ] )
    cout << msg[ 0 ] << endl, exit( 0 );
  dp = vvvvi( 2 * V + 1, vvvi( N, vvi( N, vi( 2 ) ) ) );
  dp[ V - L[ 0 ][ 0 ] ][ 0 ][ 0 ][ 0 ] = 1;
  queue< tuple< int, int, int, int > > que;
  que.emplace( V, 0, 0, 0 );
  while( not que.empty() ){
    int v, x, y, t; tie( v, x, y, t ) = que.front(); que.pop();
    // cout << "dp[ " << v << " ][ " << x << " ][ " << y << " ][ " << t << " ] = " << dp[ v ][ x ][ y ][ t ] << endl;
    int nv = v;
    int nt = t;
    if( x + 1 == Ox and y + 1 == Oy and not t )
      nv *= 2, nt = 1;
    for( int di = 0; di < 4; ++di ){
      int nx = x + dx[ di ];
      int ny = y + dy[ di ];
      if( not in_range( N, nx, ny ) ) continue;
      if( nv - L[ nx ][ ny ] > 0 )
        if( upmax( dp[ nv - L[ nx ][ ny ] ][ nx ][ ny ][ nt ], dp[ v ][ x ][ y ][ t ] ) )
          que.emplace( nv - L[ nx ][ ny ], nx, ny, nt );
    }
  }
}

void solve(){
  for( int i = 1; i <= 2 * V; ++i )
    for( int j = 0; j < 2; ++j )
      if( dp[ i ][ N - 1 ][ N - 1 ][ j ] )
        cout << msg[ 1 ] << endl, exit( 0 );
  cout << msg[ 0 ] << endl;
}

signed main(){
  ios::sync_with_stdio( 0 );
  init();
  preprocess();
  solve();
  return 0;
}