#include <iostream>
#include <cstdio>
#include <cmath>
#include <cassert>
using namespace std;

#define getchar getchar_unlocked
#define putchar putchar_unlocked

bool dot;

int in() {
    int n, c;
    while ((c = getchar()) < '0') {
        assert(c != EOF);
    }
    n = c - '0';
    while ((c = getchar()) >= '0') {
        n = n * 10 + c - '0';
    }
    if (c == '.') {
        dot = true;
    }
    return n;
}

void out(double x) {
    static char buf[20];
    sprintf(buf, "%.9f", x);
    for (int i = 0; buf[i] != '\0'; i++) {
        putchar(buf[i]);
    }
    putchar('\n');
}

const int H = 17;
const int N = 1 << H;
double lg[N];
double lgt[N];

void dfs(int k, double l, double r) {
    if (k < N) {
        lg[k] = log((l + r) / 2);
        dfs(k * 2 + 0, l, (l + r) / 2);
        dfs(k * 2 + 1, (l + r) / 2, r);
    }
}

int main() {
    const double L = 0;
    const double R = log(10);
    const double LL = -1e100;
    const double RR = log(R);

    dfs(1, L, R);

    int m = in();
    for (int i = 0; i < N; i++) {
        lgt[i] = 1e100;
    }

    while (m--) {
        int a = in();
        int b = in();
        int c = in();
        int d = dot ? in() : 0;
        double t = c + 1e-4 * d;
        if (b == 0) {
            out(pow(t, 1.0 / a));
            continue;
        }
        if (a == 0) {
            out(exp(pow(t, 1.0 / b)));
            continue;
        }
        double l = L;
        double r = R;
        double logL = LL;
        double logR = RR;
        if (lgt[c * 10000 + d] == 1e100) {
            lgt[c * 10000 + d] = log(t);
        }
        double logT = lgt[c * 10000 + d];
        int k = 1;
        for (int ii = 0; ii < H; ii++) {
            double mid = (l + r) / 2;
            if (a * mid + b * lg[k] >= logT) {
                logR = lg[k];
                k = k * 2 + 0;
                r = mid;
            } else {
                logL = lg[k];
                k = k * 2 + 1;
                l = mid;
            }
        }
        double s = (logR - logL) / (r - l);
        double ans = (logT + s * l * b - logL * b) / (s * b + a);
        out(exp(ans));
    }
}