#include #include #include #include #include #include #include #include #include #include #include #include #include #define repeat(i,n) for (int i = 0; (i) < int(n); ++(i)) #define repeat_from(i,m,n) for (int i = (m); (i) < int(n); ++(i)) #define repeat_reverse(i,n) for (int i = (n)-1; (i) >= 0; --(i)) #define repeat_from_reverse(i,m,n) for (int i = (n)-1; (i) >= int(m); --(i)) #define whole(f,x,...) ([&](decltype((x)) whole) { return (f)(begin(whole), end(whole), ## __VA_ARGS__); })(x) typedef long long ll; using namespace std; template void setmax(T & a, T const & b) { if (a < b) a = b; } template void setmin(T & a, T const & b) { if (b < a) a = b; } template auto vectors(X x, T a) { return vector(x, a); } template auto vectors(X x, Y y, Z z, Zs... zs) { auto cont = vectors(y, z, zs...); return vector(x, cont); } template map coordinate_compression_map(vector const & xs) { int n = xs.size(); vector ys(n); whole(iota, ys, 0); whole(sort, ys, [&](int i, int j) { return xs[i] < xs[j]; }); map f; for (int i : ys) { if (not f.count(xs[i])) { // make unique int j = f.size(); f[xs[i]] = j; // f[xs[i]] has a side effect, increasing the f.size() } } return f; } template vector apply_compression(map const & f, vector const & xs) { int n = xs.size(); vector ys(n); repeat (i,n) ys[i] = f.at(xs[i]); return ys; } int main() { int n, b; cin >> n >> b; vector x(n), y(n), p(n); repeat (i,n) cin >> x[i] >> y[i] >> p[i]; x = apply_compression(coordinate_compression_map(x), x); y = apply_compression(coordinate_compression_map(y), y); vector j(n); whole(iota, j, 0); whole(sort, j, [&](int i, int j) { return x[i] < x[j]; }); int ans = 0; repeat (ry,n+1) repeat (ly,ry) { int li = 0, ri = 0; int lx = 0, rx = 0; int cnt = 0, sum_p = 0; while (rx < n) { ++ rx; while (ri < n and x[j[ri]] < rx) { if (ly <= y[j[ri]] and y[j[ri]] < ry) { cnt += 1; sum_p += p[j[ri]]; } ++ ri; } while (b < sum_p) { ++ lx; while (li < n and x[j[li]] < lx) { if (ly <= y[j[li]] and y[j[li]] < ry) { cnt -= 1; sum_p -= p[j[li]]; } ++ li; } } setmax(ans, cnt); } } cout << ans << endl; return 0; }