#include #include #include #include #include #include #include #define rep(i, n) for (int i = 0; i < (n); i++) #define rrep(i, n) for (int i = (n)-1; i >= 0; i--) using namespace std; typedef long long int lli; lli MOD = 1000000007; int main() { //dp[i][j] = max(dp[j][k]+1)s.t A[j]-A[k] < A[i]-A[j] lli m; cin >> m; rep(G, m) { lli a[105], b[105]; lli n, dp[105][105] = {}, dp2[105][105] = {}; cin >> n; rep(i, n) { cin >> a[i]; b[n - 1 - i] = a[i]; } rep(i, n) { dp[i][i] = 1; dp2[i][i] = 1; } rep(i, n) for (int j = i - 1; j >= 0; j--) { rep(k, n) { if (i > j && j >= k) if (a[j] - a[k] >= 0 && a[j] - a[k] < a[i] - a[j]) dp[i][j] = max(dp[j][k] + 1, dp[i][j]); } } rep(i, n) { for (int j = i - 1; j >= 0; j--) rep(k, n) { if (i > j && j >= k) if (b[j] - b[k] >= 0 && b[j] - b[k] < b[i] - b[j]) dp2[i][j] = max(dp2[j][k] + 1, dp2[i][j]); } } lli ans = 0; rep(i, n) { rep(j, n) rep(k, n) { if (i >= j && n - i - 1 >= k) ans = max(ans, dp2[n - i - 1][k] + dp[i][j] - 1); } } cout << ans << endl; } }