#include #include #include #include #define REP(i,s,n) for(int i=(int)(s);i<(int)(n);i++) using namespace std; typedef long long int ll; typedef vector VI; typedef vector VL; typedef pair PI; ll gcd(ll a, ll b) { return b == 0 ? a : gcd(b, a % b); } ll ex_gcd(ll x, ll y, ll &a, ll &b) { if (y == 0) { a = 1; b = 0; return x; } ll q = x / y; ll r = x % y; ll res = ex_gcd(y, r, a, b); ll tmp = a - q * b; a = b; b = tmp; return res; } /* * Calculates the intersection of two arithmetic progressions, * x[n] = a + b * n and y[n] = c + d * n (n >= 0). * p1 = (a, b), p2 = (c, d) */ pair arith_prog_intersect(const pair &p1, const pair &p2) { if (p1.first > p2.first) { return arith_prog_intersect(p2, p1); } ll u, v; ll g = ex_gcd(p1.second, p2.second, u, v); ll lcm = p1.second / g * p2.second; if ((p1.first - p2.first) % g != 0) { return pair(-1, -1); } ll diff = (p2.first - p1.first) / g; diff *= v % (p1.second / g); diff %= p1.second / g; if (diff < 0) { diff += p1.second / g; } ll x = p2.first + diff * p2.second; return pair(x, lcm); } int main(void){ int n, k; cin >> n >> k; int a[100] = {}; int dp[100] = {}; REP(i, 0, n) { a[i] = i; dp[i] = -1; } REP(i, 0, k) { int x, y; cin >> x >> y; x--, y--; swap(a[x], a[y]); } REP(i, 0, n) { if (dp[i] > 0) { continue; } int c = 1; int v = a[i]; while (v != i) { v = a[v]; c++; } while (dp[v] < 0) { dp[v] = c; v = a[v]; } } int q; cin >> q; REP(loop_cnt, 0, q) { VI b(n); REP(i, 0, n) { cin >> b[i]; b[i]--; } bool ok = true; pair coef(0, 1); REP(i, 0, n) { int c = 0; int v = i; int goal = b[i]; while (c <= dp[i]) { if (goal == v) { break; } v = a[v]; c++; } if (c > dp[i]) { ok = false; break; } if (0) { cerr << "y(" << i << ")= " << c << " + " << dp[i] << " * x" << endl; } coef = arith_prog_intersect(coef, pair(c, dp[i])); if (coef.first < 0) { ok = false; break; } } if (not ok) { cout << -1 << endl; continue; } if (coef.first == 0) { coef.first = coef.second; } cout << coef.first << endl; } }