#ifdef __GNUC__ #pragma GCC optimize ("O3") #pragma GCC target ("avx") #endif #define _USE_MATH_DEFINES #include #include #include #include #include #include #include #include #include #include //#include //x C++ (G++ 4.6.4) #include #include #include #include #include #include #include //assert(); #include #include ///////// #define REP(i, x, n) for(int i = x; i < n; i++) #define rep(i,n) REP(i,0,n) ///////// typedef long long LL; typedef long double LD; typedef unsigned long long ULL; #define PII pair ///////// using namespace::std; // 最大公約数 template inline T gcd(T a, T b){return b ? gcd(b, a % b) : a;} //inline T gcd(T a, T b){return b == 0 ? a : gcd(b, a % b);} /*inline T gcd(T a,T b){ while(b != 0 ){ a = a % b; swap(a,b); } return a; }*/ // 最小公倍数 template inline T lcm(T a, T b){return a / gcd(a, b) * b;} //inline T lcm(T a, T b){return a * b / gcd(a, b);} //////////////////////////////// vector SerNum; vector SerVal(3,0); int MaxDepth; LL MinDfs = (LL)100000000000000; //pos, bool dfs(int pos, vector& vv){ if( pos >= MaxDepth ){ if( vv[0] == 1 || vv[1] == 1 || vv[2] == 1 ) return false; LL temp = vv[0]+vv[1]+vv[2]; if( temp < MinDfs ){ MinDfs = temp; SerVal = vv; } return true; } if( MinDfs < vv[0]+vv[1]+vv[2] ) return false; bool ret = false; for(int i=0;i<3;++i){ vv[i] *= SerNum[pos]; if( dfs(pos+1,vv) ){ ret = true; } vv[i] /= SerNum[pos]; } return ret; } inline void solve(){ LL N; cin >> N; int CountAll = 0; int Count = 0; vector prime; vector P; LL T = N; if( T % 2 == 0 ){ prime.push_back(2); P.push_back(0); while(T%2 == 0 ){ T /= 2; P[Count]++; ++CountAll; } ++Count; } for(LL i=3;i*i<=T;i+=2){ if( T % i == 0 ){ prime.push_back(i); P.push_back(0); while( T% i == 0 ){ T /= i; P[Count]++; ++CountAll; } ++Count; } } if( T != 1 ){ prime.push_back(T); P.push_back(1); ++Count; ++CountAll; } T = 0; // if( CountAll == 1 ){ cout << N-1 << ' ' << N-1 << endl; return; } if( CountAll == 2){ vector ans(3); for(int i=0;i ans(3,1); int SerCount = 0; /*if(Count == 1){//1種類なら while(P[0] >= 3 ){//!? ans[0] *= prime[0]; ans[1] *= prime[0]; ans[2] *= prime[0]; P[0] -= 3; } }*/ for(int i=0;i val(3,1); int P0 = P[0]; for(int a=0;2*a<=P0;++a){ if( a ) ans[0] *= SerNum[0]; ans[1] = 1; for(int b=a;a+b<=P0;++b){ int c = P0-a-b; if( c < b )break; //if(b) ans[1] *= SerNum[0]; //(SerNum[0])^c ans[1] = 1; LL mul = SerNum[0]; int temp = b; while(temp){ if( temp & 1 ) ans[1] *= mul; mul *= mul; temp >>=1; }//for(int i=0;i>=1; }//for(int i=0;i