n,m=gets.split.map &:to_i
a=Hash.new([])
m.times do
  x,y=gets.split.map &:to_i
  a[x]+=[y]
  a[y]+=[x]
end
p (t=[*0..n-1]).combination(4).count{|e|(e.map{|i|a[i]}.flatten-(t-e)).sort==(e*2).sort}