/* -*- coding: utf-8 -*- * * 489.cc: No.489 株に挑戦 - yukicoder */ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; /* constant */ const int MAX_N = 100000; const int MAX_E2 = 1 << 18; // 262144 const int INF = 1 << 30; /* typedef */ typedef long long ll; struct Val { int v, i; Val() {} Val(int _v, int _i): v(_v), i(_i) {} bool operator<(const Val &a) const { return v < a.v || (v == a.v && i > a.i); } bool operator>(const Val &a) const { return v > a.v || (v == a.v && i < a.i); } }; template struct SegTreeMax { int n, e2; T nodes[MAX_E2], initv; SegTreeMax() {} void init(int _n, T _initv) { n = _n; initv = _initv; for (e2 = 1; e2 < n; e2 <<= 1); fill(nodes, nodes + MAX_E2, initv); } T get(int i) { return nodes[e2 - 1 + i]; } void set(int i, T v) { nodes[e2 - 1 + i] = v; } void set_all() { for (int j = e2 - 2; j >= 0; j--) { int j0 = j * 2 + 1, j1 = j0 + 1; nodes[j] = max(nodes[j * 2 + 1], nodes[j * 2 + 2]); } } T max_range(int r0, int r1, int k, int i0, int i1) { if (r1 <= i0 || i1 <= r0) return initv; if (r0 <= i0 && i1 <= r1) return nodes[k]; int im = (i0 + i1) / 2; T v0 = max_range(r0, r1, k * 2 + 1, i0, im); T v1 = max_range(r0, r1, k * 2 + 2, im, i1); return max(v0, v1); } T max_range(int r0, int r1) { return max_range(r0, r1, 0, 0, e2); } }; /* global variables */ SegTreeMax stm; /* subroutines */ /* main */ int main() { int n, d, k; cin >> n >> d >> k; stm.init(n, Val(0, -1)); for (int i = 0; i < n; i++) { int xi; cin >> xi; stm.set(i, Val(xi, i)); } stm.set_all(); int maxx = 0, mini = -1, minj = -1; for (int i = 0; i < n; i++) { Val v = stm.max_range(i + 1, i + 1 + d); int x = v.v - stm.get(i).v; if (maxx < x) maxx = x, mini = i, minj = v.i; } //printf("%d %d %d\n", maxx, mini, minj); if (maxx <= 0) puts("0"); else printf("%lld\n%d %d\n", (ll)maxx * k, mini, minj); return 0; }